If the second equation is y=-3x+4 then they would be parallel and I found that by turning the first equation into y=mx+b and you subtract x from both sides of the equation and get -3y=-x+15 and then you divide both sides of the equation by -3 to get the y by itself and that turns into y=1/3x-5 and since 1/3 is the reciprocal of -3 they are perpendicular.
Answer:
x>= 11 or x>10
Step-by-step explanation:
Absolute value can be used to represent the positive counterpart of a negative number. In this case, we are asked to find a number that is less than -10, meaning from -11 to negative infinity. Since we are asked to take absolute value, we would take |-11| which equals 11, and |-∞| = ∞.
So Amy graphed a value on the number line that is greater than or equal to 11, or any value greater than 10.
*Infinity is not a real number, it represents the largest number possible, which doesn't exist since numbers can continue on forever, so it can be disregarded.*
The tan is negative in the 2nd and 4th quadrants, knowing this, the angle that equals the value that tan = 1 in the first quadrant is the tan 45° = 1, but the question restrict for 3pi/2 < theta < 2pi, so it's the same as 270° < theta < 360° (4° Quadrant), then moving the tan 45° = to this quadrant the value will be negative, tan in 4°Q = tan(360 - 45=315°) = -1.
sec theta = 1/cos theta
cos 45° =
cos values in 4°Q will be positives, so it doesn't change the signal.
sec 315° = 1/cos 315°
sec 315° = 1/square root (2)/2
sec 315 = 1/1 x 2/sqroot(2)
It’s 0.35, it’s 35/100, 35% is a bit more than a third,