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MatroZZZ [7]
3 years ago
14

Solve this question 5/8÷15/16=?​

Mathematics
2 answers:
strojnjashka [21]3 years ago
6 0

Answer:

Hellou our answer is 2/3

Step-by-step explanation:

5/8 ÷ 15/16 = 2/3

ohaa [14]3 years ago
6 0

Answer:

\frac{2}{3}

Step-by-step explanation:

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Prove that these two triangles are congruent.
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Answer:

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3 years ago
Please answer this multiple choice question CORRECTLY for 30 points and brainliest!!
JulijaS [17]

Solve the inequality for x:

5x - 3 ≤ 7x +7

Subtract 7x from each side:

-2x -3 ≤ 7

Add 3 to each side:

-2x ≤ 10

Divide both sides by -2, also when dividing  both sides of an inequality you flip the direction of the inequality sign:

x ≥ -5

The dot will be on -5, because the inequality includes equal to, the dot is solid and is greater than, the arrow will point to the right.

The correct answer is D.

4 0
3 years ago
How do you solve this question?<br><br> -3x - 7 + 5x = 15
KatRina [158]

Answer:

x=11

Step-by-step explanation:

Add 7 to both sides

-3x+5x=22

combine like terms(-3x and 5x)

2x=22

divide by 2

x=11

5 0
3 years ago
Use the domain and range of each of the following relations to determine which is a function.
Taya2010 [7]
B and C (I think they are the same)
7 0
3 years ago
The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th
Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = 59^{0} + 34^{0}

                                           = 93^{0}

Thus,

<CAB = 90^{0} - 59^{0} = 31^{0}

<CBA = 90^{0} - 34^{0} = 56^{0}

Sine rule states;

\frac{a}{Sin A} = \frac{b}{Sin B} = \frac{c}{Sin C}

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{b}{Sin 56^{0} } = \frac{242}{Sin 93^{0} }

\frac{b}{0.8290} = \frac{242}{0.9986}

cross multiply,

b = \frac{0.8290*242}{0.9986}

  = 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

\frac{a}{Sin A} = \frac{c}{Sin C}

\frac{a}{Sin 31^{0} } = \frac{242}{Sin 93^{0} }

\frac{a}{0.5150} = \frac{242}{0.9986}

cross multiply,

a = \frac{0.5150*242}{0.9986}

  = 124.8073

Sarge is about 125 feet away from the fire.

8 0
3 years ago
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