The surface area of the smaller solid is found to be 214 square meters.
<h3>What is Surface area?</h3>
The surface area is given as the sum of the area of all the faces of a three-dimensional object.
The same shape has equivalent ratio of the surface area to volume. It is given as:
![\rm \dfrac{\sqrt{area_1}}{\sqrt{area_2}}=\dfrac{\sqrt[3]{Volume_1} }{\sqrt[3]{Volume_2} }](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7B%5Csqrt%7Barea_1%7D%7D%7B%5Csqrt%7Barea_2%7D%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7BVolume_1%7D%20%7D%7B%5Csqrt%5B3%5D%7BVolume_2%7D%20%7D)
On considering the power of 6 at both the sides of the equation:
Considering area 1 and volume 1 for the larger solid, and area 2 and volume 2 for the smaller solid, substituting the values give:
By solving the above equation, the area of the smaller solid is found as 214 square meters. Thus, option B is correct.
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Answer:
Explanation:
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Answer:
C. 4.29 years
Explanation:
The computation of the payback period is shown below:
Payback period = Initial investment of the equipment ÷ Cash flows
where,
Initial investment = $30,000
And, the cash flows is
= $8,500 - $1,500
= $7,000
So the payback period is
= $30,000 ÷ $7,000
= 4.29 years
By dividing the initial investment by the cash flows we can get the payback period and the same is applied above.
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