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prisoha [69]
3 years ago
12

T is at least 8 and at most 24.

Mathematics
1 answer:
zmey [24]3 years ago
6 0

Answer:

Step-by-step explanation:

t is at least 8 and at most 24

8 ≤ t ≤ 24

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Which inequality correctly compares Two-fifths, Six-sevenths, Five-eighths, and 1?
Ronch [10]

Answer:

<u>2/5 < 5/8 < 6/7 < 1 </u>

   <u>OR</u>    

<u>1 > 6/7 > 5/8 > 2/5</u>

Step-by-step explanation:

It is required to compare Two-fifths, Six-sevenths, Five-eighths, and 1

Two-fifths = 2/5

Six-sevenths = 6/7

Five-eighths = 5/8

So, the given numbers are: 2/5, 6/7, 5/8, and 1

We need to make the numbers in order from the least to the greatest or from the greatest to the least

The easy method is convert the rational numbers to decimal numbers

So,

2/5 = 0.4

6/7 ≈ 0.857

5/8 = 0.625

1 = 1

So, the numbers form the least to the greatest are:

0.4 , 0.625 , 0.857 , 1

So,

2/5 , 5/8 , 6/7 , 1

The inequality correctly compares the numbers are:

<u>2/5 < 5/8 < 6/7 < 1</u>

Or can be written from the greatest to the least as:

<u>1 > 6/7 > 5/8 > 2/5 </u>

6 0
4 years ago
10 divided by 2-(16 divided by 4) +14
ankoles [38]

Answer:

15

Step-by-step explanation:

okay so you gotta use pemdas (p = parentheses, e = exponents, m = multiplication, d = division, a = addition, s = subtraction), but for the multiplication/division and addition/subtraction parts, if  division or subtraction happens first then you must do it first rather than doing multiplication or addition first

10 / 2 -(16/4) + 14

10 / 2 -(4) + 14

5 - 4 + 14

1 + 14

15

7 0
4 years ago
Read 2 more answers
A group of students wanted to investigate the claim that the average number of text messages sent yesterday by
Likurg_2 [28]
First we need to write the null and alternate hypothesis for this case.

Let x be the average number of text message sent. Then

Null hypothesis: x = 100
Alternate hypothesis: x > 100

The p value is 0.0853

If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.

If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.

If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
7 0
3 years ago
5s-(100+2s =4s-2(10+s) how much boxes would they need to sell to get a equal amount each group must sell to have equal profits.
antoniya [11.8K]
5s-100-2s=4s-20-2s
3s-100. = 2s-20
+20. +20
3s-80. = 2s
-3s. -3s
-80. = -1s
-1 -1
80. = s

s=80
6 0
3 years ago
Lei had php 150. She spend php 48 for spaghetti and Php 12. For the drinks what percent of her money was left​
musickatia [10]

Answer:

She has 60% of money left.

Step-by-step explanation:

You have to find out how much Php that Lei has left :

Php 150 - Php 48 - Php 12 = Php 90

She has a remaining of Php 90. Next, you have to find the percentage by dividing hy original amount and then, multiply by 100 :

(90/150)×100 = (3/5)×100 = 60%

7 0
4 years ago
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