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kkurt [141]
2 years ago
5

Which of the following rational functions is graphed below?

Mathematics
1 answer:
34kurt2 years ago
7 0

Answer:

B

Step-by-step explanation:

trust me brooooooooooo

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Jacob counts 37 ants on the sidewalk and 11 ants on the grass.how many ants does Joes count?
Lera25 [3.4K]
Jacob counts 48 ants all together 37 + 11 = 48
4 0
3 years ago
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F(x)=⅔x⁴-12x²+x+⅞ its apolynomial function or its not polynomial function
baherus [9]

Answer:

apolinomlia

Step-by-step explanation:

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3 years ago
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A clothing business finds there is a linear relationship between the number of shirts, Q ,it can sell and the price, P , it can
Vlad [161]

Answer:

P = -0.004Q + 149

Step-by-step explanation:

The general form of the linear equation is:

P=aQ+b

The slope of the equation (a) can be found by using the two given points (4,000; $133) and (27,000; $41)

a = \frac{\$41-\$133}{27,000-4,000}\\a=-0.004

Applying the point (4,000; $133) to the equation below yields in the linear equation for Price as a function of the number of shirts:

P-P_0=a(Q-Q_0)\\P-133=-0.004(Q-4,000)\\P = -0.004Q+149

The linear equation is:

P = -0.004Q + 149

8 0
3 years ago
Which of the following segments is a radius of OO?
Sergio039 [100]

Answer:

RO

Step-by-step explanation:

3 0
3 years ago
Find the intersection points using substitution or elimination for each system of equations:
natka813 [3]

Answer:

Step-by-step explanation:

Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.

Problem 1:

(x²)/4 +y²= 1

y= x+1

*substitute for y*

Now we have a one-variable equation we can solve-

x²/4 + (x+1)² = 1

x²/4 + (x+1)(x+1)= 1

x²/4 + x²+2x+1= 1

*subtract 1 from both sides to set equal to 0*

x²/4 +x^2+2x=0

x²/4 can also be 1/4 * x²

1/4 * x² +1*x² +2x = 0

*combine like terms*

5/4 * x^2+2x+ 0 =0

now, you can use the quadratic equation to solve for x

a= 5/4

b= 2

c=0

the syntax on this will be rough, but I'll do my best...

x= (-b ± √(b²-4ac))/(2a)

x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))

x= (-2 ±√(4-0))/(2.5)

x= (-2±2)/2.5

x will have 2 answers because of ±

x= 0 or x= 1.6

now plug that back into one of the equations and solve.

y= 0+1 = 1

y= 1.6+1= 2.6

Hopefully this explanation was enough to help you solve problem 2.

Problem 2:

x² + y² -16y +39= 0

y²- x² -9= 0

6 0
3 years ago
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