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Lelechka [254]
3 years ago
11

A right triangle has a height of 20 centimeters and a base of 10 centimeters. What is the area of the triangle?

Mathematics
2 answers:
Damm [24]3 years ago
7 0

Answer:

100

Step-by-step explanation:

the area is given by half base times height and we are already given the base and the height so take a half times 10 times 20 .

juin [17]3 years ago
4 0

Answer:

100 cm^2

Step-by-step explanation:

The formula for triangle area is L x W / 2.

20 x 10 = 200

200 / 2 = 100

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What is the best approximation of the surface area of this right cone?
inn [45]
\bf \textit{total surface area of a cone}\\\\
s=\pi r\sqrt{r^2+h^2}+\pi r^2\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=12\\
h=9
\end{cases}
\\\\\\
s=\pi (12)\sqrt{12^2+9^2}+\pi (12^2)\implies s=12\pi \sqrt{225}+144\pi 
\\\\\\
s=12\pi (15)+144\pi \implies s=180\pi +144\pi \implies s=324\pi
8 0
3 years ago
Find the average value of the function f(x, y, z) = 5x2z 5y2z over the region enclosed by the paraboloid z = 9 − x2 − y2 and the
Katyanochek1 [597]
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin. 

<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>

<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>

<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>

<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>


<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>

<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>

<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>

<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>

<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
4 0
3 years ago
What is 342 in fraction form
oee [108]

Answer:

342 / 1

Step-by-step explanation:

342 / 1 = 342

342 in fraction form is 342 / 1.

7 0
2 years ago
How do you solve f(x) = x2 + x - 20?​
Darina [25.2K]

\huge \bf༆ Answer ༄

Let's solve ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: {x}^{2}  + x - 20

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: {x}^{2}  + 5x - 4x - 20

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x(x + 5) - 4(x + 5)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(x + 5)(x -  4)

It's factorized now ~ And if you want to find the zeros then equate the expression with 0.

And you will get ;

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x =  - 5 \:  \: and \:  \: 4

4 0
2 years ago
Please help me solve this problem​
Stella [2.4K]

Answer:

  • See below

Step-by-step explanation:

<u>Since all graphs pass throught the origin, they all have the form of:</u>

  • y = ax², where a- coefficient

The coefficient of each graph's equation can be calculated based on the given pairs of points.

Each of them calculated for you and attached below.

8 0
2 years ago
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