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slamgirl [31]
3 years ago
13

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 92.6-cm and a standard devi

ation of 2-cm. For shipment, 12 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 92-cm and 92.4-cm. Enter your answer as a number accurate to 4 decimal places.
Mathematics
1 answer:
Tatiana [17]3 years ago
8 0

Answer: 0.2140

Step-by-step explanation:

Given : A company produces steel rods. The lengths of the steel rods are normally distributed with

\mu=92.6 \text{ cm}

\sigma=2\text{ cm}

Sample size : n=12

Let x be the length of randomly selected item.

z-score : z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}

For x=92 cm

z=\dfrac{92-92.6}{\dfrac{2}{\sqrt{12}}}\approx-1.04

For x=92.4 cm

z=\dfrac{92.4-92.6}{\dfrac{2}{\sqrt{12}}}\approx-0.35

The probability that the average length of a randomly selected bundle of steel rods is between 92-cm and 92.4-cm by using the standard normal distribution table

= P(92

= 0.3631693-0.14917=0.2139993\approx0.2140

Hence, the probability that the average length of a randomly selected bundle of steel rods is between 92-cm and 92.4-cm is 0.2140.

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a student worked out at the gym continuously for 50 minutes. The graph shows the remaining percentage of the workout f(x) as a l
SashulF [63]

Answer:

Domain: All real numbers greater than or equal to 0 and less than or equal to 50

Range: All real numbers greater than or equal to 0 and less than or equal to 100

Step-by-step explanation

The workout is at 100% at 50 mins. Anything less would be under these two numbers.  Since the percentage of workout is on the y-axis, anything between zero and 100 can be possible. The time is on the x-axis, so anything 0 to 50 can be possible.  

8 0
3 years ago
Start solving the following x+5=11
dimulka [17.4K]

Answer:

6

Step-by-step explanation:

x=11-5=6

therefore x=6

6 0
3 years ago
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The best player on a basketball team makes 85% of all free throws. The second-best player makes
xxTIMURxx [149]

Answer:

i. Estimated number of free throws of the best player = 0.85 * 40

ii. 34 free throws

Step-by-step explanation:

Percentage of free throws made by the best player = 85%

Percentage of free throws made by the second best player = 75%

Percentage of free throws made by the third best player = 70%

Therefore, for 40 attempts;

i. Estimated number of free throws made by the best player = 85% x 40

                                                         = 0.85 x 40

                                                         = 34

ii. Estimated number of free throws made by the second best player = 75%x 40

                                                                 = 0.75 x 40

                                                                 = 30

iii. Estimated number of free throws made by the third best player = 70% x 40

                                                                   = 0.70 x 40

                                                                   = 28

Thus, the equation that gives the estimated number of free throws is 0.85 * 40.

The best player will make about 34 free throws.

8 0
3 years ago
PLEASE HELP ASAP!!
Arada [10]
This is like the equivalent to a jar with 4 green balls and 6 white balls, where you are picking 3. (The 4 green balls signify the friends from kindergarten.) 

You want to solve the probability that the first two balls are green and the third is white. 
First draw --> 4 green out of 10 balls --> 4/10 = 2/5 

Second draw --> 3 green out of 9 balls --> 3/9 = 1/3 

Third draw --> 6 white out of 8 balls --> 6/8 = 3/4 


2/5 x 1/3 x 3/4 

= 6/60 

= 1/10 


so the answer is 1/10 (or 10%)
6 0
3 years ago
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The segment below is dilated by a scale factor of 5 to form N'O'. What is the<br> measure of N'O'?
erma4kov [3.2K]

Answer:

N'O' = 25

Step-by-step explanation:

N'O' = 5 × NO = 5 × 5 = 25

7 0
3 years ago
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