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MAVERICK [17]
4 years ago
7

You have a web application hosted in AWS cloud where the application logs are sent to Amazon CloudWatch. Lately, the web applica

tion has recently been encountering some errors which can be resolved simply by restarting the instance. What will you do to automatically restart the EC2 instances whenever the same application error occurs?
Computers and Technology
1 answer:
Ratling [72]4 years ago
5 0

Answer:

The answer of the question is given below.

Explanation:

We will follow certain steps to reboot the EC2 automatically if there is the identical application failure.

  • To develop the following metric, check initially towards current CloudWatch logs for keywords relevant to that of the software failure.
  • Then develop that metric CloudWatch alert which often invokes the operation to reboot the EC2 case.

You may only assign single launch customization for such an Auto Scaling team at a period, and when you've set up this, you will not change a launch customization.

Thus, you need to develop a launch customization then upgrade the Auto Scaling team with that of the latest launch customization when you would like to adjust the launch customization for such an Auto Scaling party.

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That Theory is known as "Big-Bang Theory"

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3 years ago
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Write a program that, for four points A, B, C and P, which a) Draws a triangle formed by ABC and a small cross showing the posit
Degger [83]

Answer:

import java.awt.*;

import java.applet.*;

public class DrawTrainlge extends Applet{

static double findDistance(float x1, float y1,float a, float b,float c){

double dis = Math.abs(((a * x1 + b * y1 + c)) /  (Math.sqrt(a * a + b * b)));

return dis;

}

public void paint(Graphics g){

Point[] point = new Point[4];

g.drawLine(point[0].x , point[0].y , point[1].x , point[1].y);

g.drawLine(point[0].x , point[0].y , point[2].x , point[2].y);

g.drawLine(point[2].x , point[2].y , point[1].x , point[1].y);

double newdistance = 9999999;

for(int i=0;i<3;i++){

            int first = (i+1)%3;

            int second = i;

            float a = point[first].y - point[second].y;

            float b = point[second].x - point[first].x;

            float c = a*(point[second].x) + b*(point[second].y);

            double dis = findDistance(point[3].x,point[3].y,a,b,c);

            if(newdistance > dis){

               dis = newdistance;

         }

}

g.drawString("Shortest Distance");

g.drawString(dis);

}

}

Explanation:

  • Inside the findDistance method, find the distance  by using the following formula:

Math.abs(((a * x1 + b * y1 + c)) /  (Math.sqrt(a * a + b * b)))

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3 years ago
When using an online media source, students should ensure the information is
OLEGan [10]
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Nat2105 [25]

Answer:

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Difference between GIAC and  InfoSec certifications is given below

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3 years ago
Which file types have .exe and .png as their extensions?
cricket20 [7]
EXE files are executable files.
PNG files are picture files like JPEG etc.
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4 years ago
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