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MAVERICK [17]
3 years ago
7

You have a web application hosted in AWS cloud where the application logs are sent to Amazon CloudWatch. Lately, the web applica

tion has recently been encountering some errors which can be resolved simply by restarting the instance. What will you do to automatically restart the EC2 instances whenever the same application error occurs?
Computers and Technology
1 answer:
Ratling [72]3 years ago
5 0

Answer:

The answer of the question is given below.

Explanation:

We will follow certain steps to reboot the EC2 automatically if there is the identical application failure.

  • To develop the following metric, check initially towards current CloudWatch logs for keywords relevant to that of the software failure.
  • Then develop that metric CloudWatch alert which often invokes the operation to reboot the EC2 case.

You may only assign single launch customization for such an Auto Scaling team at a period, and when you've set up this, you will not change a launch customization.

Thus, you need to develop a launch customization then upgrade the Auto Scaling team with that of the latest launch customization when you would like to adjust the launch customization for such an Auto Scaling party.

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Suppose the daytime processing load consists of 65% CPU activity and 35% disk activity. Your customers are complaining that the
bekas [8.4K]

Answer:

The answer to this question can be described as follows:

Explanation:

Given data:

Performance of the CPU:  

The Fastest Factor Fraction of Work:

f_1=65 \% \\\\=\frac{65}{100} \\\\ =0.65

Current Feature Speedup:

K_1= 1.5

CPU upgrade=6000

Disk activity:

The quickest part is the proportion of the work performed:

Current Feature Speedup:

k_2=3

Disk upgrade=8000

System speedup formula:

s=\frac{1}{(1-f)+(\frac{f}{k})}

Finding the CPU activity and disk activity by above formula:

CPU activity:

S_{CPU}=\frac{1}{(1-f_1)+(\frac{f_1}{k_1})} \\\\=\frac{1}{(1-0.65)+(\frac{0.65}{1.5})} \\\\=1.276 \%  ...\rightarrow (1) \\

Disk activity:

S_{DISK} = (\frac{1}{(1-f_2)+\frac{f_2}{k_2}}) \\\\ S_{DISK} = (\frac{1}{(1-0.35)+\frac{0.35}{3}}) \\\\ = -0.5\% .... \rightarrow (2)

CPU:

Formula for CPU upgrade:

= \frac{CPU \ upgrade}{S_{CPU}}\\\\= \frac{\$ 6,000}{1.276}\\\\= 4702.19....(3)

DISK:

Formula for DISK upgrade:

=\frac{Disk upgrade} {S_{DISK}}\\\\= \frac{\$ 8000}{-0.5 \% }\\\\= - 16000....(4)

equation (3) and (4),

Thus, for the least money the CPU alternative is the best performance upgrade.

b)

From (3) and (4) result,

The disc choice is therefore the best choice for a quicker system if you ever don't care about the cost.

c)

The break-event point for the upgrades:

=4702.19 x-0.5

= -2351.095

From (2) and (3))

Therefore, when you pay the sum for disc upgrades, all is equal $ -2351.095

4 0
3 years ago
Yo don't take this down just join this server you can say what ever
MrMuchimi

Answer:

Stop this and watch some prawns

4 0
3 years ago
Your network consists of three sites and two domains, with some computers from both domains at each site. Each site has certain
Zinaida [17]

Answer:

Create three GPOs, one for each site, with the appropriate security settings. Apply the GPOs to the corresponding site, and enforce the GPO.

3 0
3 years ago
With segmentation, a logical address consists of _____.
Dovator [93]
I dont under stand the question 
8 0
3 years ago
2.19.5: Circle Pyramid 2.0
liubo4ka [24]

Answer:

def move_to_row(num_circle):

x_value = -((num_circle*50)/2)

y_value = -250 +(50*row_value)

penup()

setposition(x_value,y_value)

pendown()

def draw_circle_row(num_circle):

for i in range(num_circle):

endown()

circle(radius)

penup()

forward(diameter)

#### main part

speed(0)

radius = 25

diameter = radius * 2

row_value = 1

num_circle = int(input("How many circle on the bottom row? (8 or less): "))

penup()

for i in range(num_circle):

move_to_row(num_circle)

row_value=row_value+1

draw_circle_row(num_circle)

num_circle=num_circle-1

8 0
3 years ago
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