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oksano4ka [1.4K]
3 years ago
9

Round to the nearest hundredth 26.9816

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
4 0

\huge{\boxed{26.98}}

The hundredths place is the second place after the decimal point. In this case, it is 8.

We can round it by looking at the next place to the right, which is a 1. 1 is less than 5, so we can just cut off everything after the hundredths place. This leaves an answer of \boxed{26.98}.

skad [1K]3 years ago
4 0
26.98 is rounded to the nearest hundredth
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Please help me with my homework.
Blababa [14]

Answer:

-3x + 6

Step-by-step explanation:

-3(x - 2) to find the equivalent of this expression, we need to multiply inside the parenthesis with -3 (with both x and -2)

-3(x - 2 = -3x + 6 (two negative expressions multiplied results in positive)

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d

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Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A
Vlad [161]

Answer:

y(x)=sin(2x)+2cos(2x)

Step-by-step explanation:

y''+4y=0

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e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda

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Using the characteristic equation:

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Factor out e^{\lambda x}

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Therefore the zeros must come from the polynomial:

\lambda^2+4 =0

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\lambda =\pm2i

These roots give the next solutions:

y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}

Where c_1 and c_2 are arbitrary constants. Now, the general solution is the sum of the previous solutions:

y(x)=c_1 e^{2ix} +c_2 e^{-2ix}

Using Euler's identity:

e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)

y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\

Redefine:

i(c_1-c_2)=c_1\\\\c_1+c_2=c_2

Since these are arbitrary constants

y(x)=c_1sin(2x)+c_2cos(2x)

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Finally, the solution is given by:

y(x)=sin(2x)+2cos(2x)

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I can give you a link  https://youtu.be/aUy-_WnEV30 . I hope this answers your problem, and gives you greater insight. Sorry I couldn't do more :(

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