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bonufazy [111]
2 years ago
11

Which of these is not an equation

Mathematics
1 answer:
diamong [38]2 years ago
3 0
Where is the data/info at
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Solve -3/5+1/5>7/20 Drag and drop a number or symbol into each box to show the solution.
Korolek [52]
Not sure what you mean by drag and drop but Im going to attempt this.

-3/5 = -12/20
1/5 = 4/20

That makes no sense. It should be -8/20 < 7/20?


3 0
2 years ago
Which equation represents the relationship between the x-and y-values shown in the table?
suter [353]
Y=3x-4

if you’re ever unsure just plug in the numbers on the chart into the equations and see which ones work
5 0
2 years ago
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A small rocket is fired from a launch pad 10 m above the ground with an initial velocity left angle 250 comma 450 comma 500 righ
jonny [76]

Let \vec r(t),\vec v(t),\vec a(t) denote the rocket's position, velocity, and acceleration vectors at time t.

We're given its initial position

\vec r(0)=\langle0,0,10\rangle\,\mathrm m

and velocity

\vec v(0)=\langle250,450,500\rangle\dfrac{\rm m}{\rm s}

Immediately after launch, the rocket is subject to gravity, so its acceleration is

\vec a(t)=\langle0,2.5,-g\rangle\dfrac{\rm m}{\mathrm s^2}

where g=9.8\frac{\rm m}{\mathrm s^2}.

a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,

\vec v(t)=\left(\vec v(0)+\displaystyle\int_0^t\vec a(u)\,\mathrm du\right)\dfrac{\rm m}{\rm s}

\vec v(t)=\left(\langle250,450,500\rangle+\langle0,2.5u,-gu\rangle\bigg|_0^t\right)\dfrac{\rm m}{\rm s}

(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

\boxed{\vec v(t)=\langle250,450+2.5t,500-gt\rangle\dfrac{\rm m}{\rm s}}

and

\vec r(t)=\left(\vec r(0)+\displaystyle\int_0^t\vec v(u)\,\mathrm du\right)\,\rm m

\vec r(t)=\left(\langle0,0,10\rangle+\left\langle250u,450u+1.25u^2,500u-\dfrac g2u^2\right\rangle\bigg|_0^t\right)\,\rm m

\boxed{\vec r(t)=\left\langle250t,450t+1.25t^2,10+500t-\dfrac g2t^2\right\rangle\,\rm m}

b. The rocket stays in the air for as long as it takes until z=0, where z is the z-component of the position vector.

10+500t-\dfrac g2t^2=0\implies t\approx102\,\rm s

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

\boxed{\|\vec r(102\,\mathrm s)\|\approx64,233\,\rm m}

c. The rocket reaches its maximum height when its vertical velocity (the z-component) is 0, at which point we have

-\left(500\dfrac{\rm m}{\rm s}\right)^2=-2g(z_{\rm max}-10\,\mathrm m)

\implies\boxed{z_{\rm max}=125,010\,\rm m}

7 0
2 years ago
AI
Iteru [2.4K]

In order to find the equivalent expression, let's use the following property:

a-(-b)=a+b

In other words, when subtracting a negative number, we can just add the corresponding positive number, that is, switch the two negative signs for a positive sign.

So we have that:

\begin{gathered} 18\frac{1}{5}-(-22\frac{2}{5})-(-40\frac{1}{5}) \\ =18\frac{1}{5}+22\frac{2}{5}+40\frac{1}{5} \end{gathered}

Therefore the correct option is D.

8 0
7 months ago
What is 5 + 5 + 5 + 5 + 6 + 7 + 5 + 6 + 4 + 4+ 4 + 6+ 3 + 3 + 1 + 9?
elena-14-01-66 [18.8K]

Answer:

5,555,675,644,463,319

Step-by-step explanation:

plz mark brainly

                                                         JK 78 LOL

7 0
3 years ago
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