Answer:
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Step-by-step explanation:
denoting A= a piece is defective , Bi = a piece is defective from the i-th supplier and Ci= choosing a piece from the the i-th supplier
then
P(A)= ∑ P(Bi)*P(C) with i from 1 to 3
P(A)= ∑ 5/100 * 24/100 + 10/100 * 36/100 + 6/100 * 40/100 = 9/125
from the theorem of Bayes
P(Cz/A)= P(Cz∩A)/P(A)
where
P(Cz/A) = probability of choosing a piece from Z , given that a defective part was obtained
P(Cz∩A)= probability of choosing a piece from Z that is defective = P(Bz) = 6/100
therefore
P(Cz/A)= P(Cz∩A)/P(A) = P(Bz)/P(A)= 6/100/(9/125) = 5/6 (83.33%)
thus the probability that a part was received from supplier Z , given that is defective is 5/6 (83.33%)
Answer:
2000? ... assume $2000
Resale Value = $2000*(1 - 0.25)t/yr
where: t = number of year after purchase
at t = 3 yr
Resale Value = $2000*(1 - 0.25)3 = $843.75
checking: at t = 0 $2000 (purchase price)
at t = 1 yr $2000 - 0.25*$2000 = $2000 - $500 = $1500
at t = 2 yr $1500 - 0.25*$1500 = $1500 - $375 = $1125
at t = 3 yr $1125 - 0.25*$1125 = $1125 - $281.25 = $843.75
no because you're more than likely going to lose your money
Here is your answer and an explanation
Answer: y = -2/3x
Explanation:
This can be determined by calculating the gradient of the straight line, using:
m=ΔyΔx
=−6−34−(−2)
=−96
=−32
Then we use the slope-point form of the straight line:
y−y1=m(x−x1)
to give:
y−3=−32(x−(−2))
∴y−3=−32(x+2)
∴y−3=−32x−3
∴y=−32x
Answer:
one
Step-by-step explanation:
i have no idea what kind of test ur taking my guy but have fun
