All categories

3 years ago

Find the value of x in the figure

Mathematics

1 answer:

quester [9]3 years ago

4 0

Answer:

the correct ans is 37 .

(4x+2)° = 150°.... opposite angles of measure are

congruent.

4x+2 = 150

4x = 150-2

4x = 148

x = 148/4

x = 37.

You might be interested in

I need help plzs ill give you brainiest

BARSIC [14]

The answer is A, if the two values are the same because equivalent means equal to one another, or the same.
Hope this helps!

8 0

3 years ago

What is the slope of the line that passes through (-1, -7/3,) (8/3, 5)

Lera25 [3.4K]

Answer:

slope is m=2

Step-by-step explanation:

5-(-7/3)=22/3

divided by

8/3-(-1)=11/3

=22/3*3/11=2/1*1/1=2

8 0

3 years ago

Which of the following is the product of the rational expressions shown below? 7x/x-4•x/x+7

Gre4nikov [31]

<h2>The product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}$ .</h2>

Step-by-step explanation:

We have,

$\dfrac{7x}{x-4}.\dfrac{x}{x+7}$

To find, the product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7}$ = ?

∴ $\dfrac{7x}{x-4}.\dfrac{x}{x+7}$

= $\dfrac{7x.x}{(x-4)(x+7)}$

= $\dfrac{7x^2}{(x(x+7)-4(x+7)}$

= $\dfrac{7x^2}{x^2+7x-4x-28}$

= $\dfrac{7x^2}{x^2+3x-28}$

Thus, the product of the rational expressions $\dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}$ .

7 0

3 years ago

Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part

katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

$(26)x = 1$

$(50)x = 1$

and:

$(2^6)^x = 1$

$(5^0)^x = 1$

Solving: $(26)x = 1$ and $(50)x = 1$

$(26)x = 1$

Divide both sides by 26

$x = \frac{1}{26}$

$(50)x = 1$

Divide both sides by 50

$x = \frac{1}{50}$

Solving $(2^6)^x = 1$ and $(5^0)^x = 1$

$(2^6)^x = 1$

Express 1 as 2^0

$(2^6)^x = 2^0$

Remove bracket

$2^{6x} = 2^0$

Cancel out 2

$6x = 0$

Divide both sides by 6

$x = \frac{0}{6}$

$x = 0$

$(5^0)^x = 1$

Express 1 as 5^0

$(5^0)^x = 5^0$

Cancel out 5^0

$x = 1$

8 0

3 years ago

Find the sum and express it in the simplest form.(2y^2+9y+4)+(-3y^2-3y-9)

vampirchik [111]

Since the operation between the two sets of parentheses is addition, we don't have to do anything with it, and can remove the parentheses.
Our new expression is: 2y^2+9y+4-3y^2-3y-9

Now, we just add like terms together to solve for the simplest form of the expression.
2y^2+9y+4-3y^2-3y-9
(2-3)y^2+(9-3)y+(4-9)
-y^2+6y-5

Our final answer is -y^2+6y-5.

8 0

3 years ago