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jenyasd209 [6]
4 years ago
7

ABC company’s stock dropped from 25 3/8 to 22 1/4 during a one month period of time.. How much did ABC’s stock fall during this

period of time? A. 3 1/8 B. 3 1/4 C. 4 1/4 D. 47 5/8
Mathematics
1 answer:
Gwar [14]4 years ago
3 0
We are given with two numerics in a mixed fraction form and is asked for the difference between the two. in this case, we subtract first the whole numbers: 25-22 equal to 3. Then convert the two fractions to similar fractions. the difference is 1/8. Hence the answer is 3 1/8
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Can someone answer this? I got 180 cubic inches but it wasn't right. Please help.
cricket20 [7]
Of course 180 is correct if the length and breadth of both the container s are same
6 0
3 years ago
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What is the range of the function shown in this table?<br> х 3 4 5 6 y 4 4 2 5
Alekssandra [29.7K]

Answer:

2,4,5

Step-by-step explanation:

Do not repeat numbers, u need to put them in order from least to greatest, and range is for the y

6 0
3 years ago
A shirt that cost $420 was discounted 20% for Bloomingdale's one day sale. When the sale was over, the shirt was marked up 20%.
Maurinko [17]

Answer:

$504

Step-by-step explanation:

Step one:

given data

A shirt that cost $420

we are told that the shirt was on a discount sale of 20%, so when the discount is over the price will return to $420, we are then told that the shirt was marked up 20%.

Step two:

Hence the new cost is

=20/100*420+ 420

=0.2*420+420

=84+420

=$504

5 0
3 years ago
Count by 1s or 5s. Write the first five numbers you would count, starting at 15.
sesenic [268]
Count by 1s or 5s. Write the first five numbers you would count, starting at 15.Starting by 1s
1. 16
2. 17
3. 18
4. 19
5. 20

Next is by 5s
1. 20
2. 25
3. 30
4. 35
5. 40

7 0
4 years ago
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A person 6ft tall stands 10ft from point P directly beneath a lantern hanging 30 ft above the ground. The lantern start to fall,
xxMikexx [17]

Answer:

\frac{dL}{dt}=30 \frac{ft}{s}

Step-by-step explanation:

In order to solve this it is always a good idea to start by drawing a diagram of the situation (See attached picture).

From the diagram we can see that we are dealing with similar triangles. We can use similar triangles to build an equation that relates the length of the shadow with the height of the lamp, so we get:

\frac{L}{6}=\frac{10+L}{h}

the height of the lamp can be found by subtracting the 16t^{2} distance the lamp falls in a given time t from the original 30ft the lamp was located at.

So the equation will now lok like this:

\frac{L}{6}=\frac{10+L}{30-16t^{2}}

So now we can solve the equation for L, we can start by multiplying by the LCD SO WE GET:

L(30-16t^{2})=6(10+L)

next, we can distribute the right side of the equation so we get:

L(30-16t^{2})=60+6L

and subtract 6L from both sides so we get:

L(30-16t^{2})-6L=60

and factor L, so we get:

L(30-16t^{2}-6)=60

and solve for L:

L=\frac{60}{24-16t^{2}}

now, we can differentiate this equation by using the chain rule, so we get:

dL=-\frac{60}{(24-16t^{2})^{2}}(-32t)dt

which can be simplified to:

\frac{dL}{dt}=\frac{1920t}{(24-16t^{2})^{2}}

and now we can substitute t for 1s so we get:

\frac{dL}{dt}=\frac{1920(1)}{(24-16(1)^{2})^{2}}

\frac{dL}{dt}=30 \frac{ft}{s}

7 0
3 years ago
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