The nth term of the sequence whose integers are between 1 -7 such that there is the permission of repetition but no two consecutive digits must be even is 1.254 × 10¹¹
<h3>What are consecutive numbers?</h3>
Consecutive numbers are those numbers that succeed each other in increasing order from least to greatest. The numbers that are given:
- 1, 2, 3, 4, 5, 6, or 7 are all consecutive.
Now, suppose a (n) denotes the number of n-digit positive integers as stated in the question, thereby using:
- 1, 2, 3, 4, 5, 6, or 7 with the permission of repetition; no two consecutive digits are even.
Then, the number of n can be computed as n!
= (7!) × (6!) × (5!) × (4!) × (3!) × (2!) × (1!)
= 1.254 × 10¹¹
Learn more about consecutive numbers here:
brainly.com/question/26352026
For this question you can say:
16g - 48g = -32g
and 32h - 40h = -8h
so you will have:
-32g - 8h and you can factor -8 so you will have:
-8(4g + h) :)))
i hope this is helpful
have a nice day
Answer:
x=0
Step-by-step explanation:
0/3 = 0
0+5=5
Y=2(4)+8
y=8+8
y=16
Hope this helps :)