We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
Answer: 0.355,0.405)
Step-by-step explanation:
Given : Significance level : 
Number of subjects (n) = 2455
Number of surveys returned = 931
The probability of surveys get return will be :-

The confidence interval for proportion is given by :-


Hence, the 99% confidence interval for the proportion of returned surveys : (0.355,0.405)
I hope this helps you
4×[x-y=1] 4x-4y=4
3x+4y+4x-4y=5+4
7x=9 x=9/7
9/7-y=1 y=9/7-1 y=2/7
3.4 x 10^8 is the answer m888888888888888