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Schach [20]
3 years ago
11

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Mathematics
1 answer:
yuradex [85]3 years ago
6 0

Answer:

Converges to 0

Step-by-step explanation:

Given is an improper integral  where a= -infinity, b = infinity and

ff(x) = \frac{x}{x^2+1}

\int\limits^a_b {f(x)} \, dx

This resembles the above integral where a = -b

f(x) let us check whether odd or even or neither

f(-x) = \frac{-x}{x^2+1}=-f(x)

Since f(x) is odd function and integral is of the form -a to a by properties of integrals, this value is 0

Hence answer is 0

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Can you help me with this question please
solniwko [45]

Answer:

the answer is 9^8

Step-by-step explanation:

9^3 * 9^5 = 9^ 3 + 5 = 9^8

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3 years ago
What is the sum of (x - 8) - (2x + 2)
Dahasolnce [82]

Answer:

the answer is 4

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2 years ago
Read 2 more answers
Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)
Pani-rosa [81]

Answer:

ABCD is not a parallelogram

Step-by-step explanation:

Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)

We have to find the length of the sides of the parallelogram using the formula below

= √(x2 - x1)² + (y2 - y1)² when given vertices (x1, y1) and (x2, y2)

For side AB

A(-3,2) B(-3,3)

= √(-3 -(-3))² + (3 -2)²

= √0² + 1²

= √1

= 1 unit

For side BC

B(-3,3) C (5,-3)

= √(5 -(-3))² + (-3 -3)²

= √8² + -6²

= √64 + 36

= √100

= 10 units

For side CD

C (5,-3) D (-1.-5)

= √(-1 - 5)² + (-5 - (-3))²

= √-6² + -2²

= √36 + 4

= √40 units

For sides AD

A(-3,2) D (-1.-5)

= √(-1 - (-3))² + (-5 -2)²

= √(2² + -7²)

= √(4 + 49)

= √53 units

A parallelogram is a quadrilateral with it's opposite sides equal

From the above calculation

Side AB ≠ CD

BC ≠ AD

Therefore, ABCD is not a parallelogram

3 0
3 years ago
We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys
marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation    

\bar X=19.2 represent the battery life sample mean    

\sigma=2.5 represent the population standard deviation    

n=25 sample size    

\mu_o =18 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:    

Null hypothesis:\mu = 18    

Alternative hypothesis:\mu \neq 18    

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis:\mu \leq 18    

Alternative hypothesis:\mu > 18  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4    

4) P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=25-1=24  

Since is a two tailed test for parts I and II, the p value would be:    

p_v =2*P(t_{(24)}>2.4)=0.0245

And for part III since we have a one right tailed test the p value is:

p_v =P(t_{(24)}>2.4)=0.0122

5) Conclusion    

I. This finding is significant for a two-tailed test at .05.

Since the p_v. We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

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3 years ago
The table shows list of walking trails in the United States. Latisha walked the KATY trail six days last week. How many miles di
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How long is the trail on your table then multiply by 6.
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