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Schach [20]
3 years ago
11

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Mathematics
1 answer:
yuradex [85]3 years ago
6 0

Answer:

Converges to 0

Step-by-step explanation:

Given is an improper integral  where a= -infinity, b = infinity and

ff(x) = \frac{x}{x^2+1}

\int\limits^a_b {f(x)} \, dx

This resembles the above integral where a = -b

f(x) let us check whether odd or even or neither

f(-x) = \frac{-x}{x^2+1}=-f(x)

Since f(x) is odd function and integral is of the form -a to a by properties of integrals, this value is 0

Hence answer is 0

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