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strojnjashka [21]
3 years ago
7

Can you help me with this question please

Mathematics
1 answer:
solniwko [45]3 years ago
7 0

Answer:

the answer is 9^8

Step-by-step explanation:

9^3 * 9^5 = 9^ 3 + 5 = 9^8

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What is the volume of a volleyball with a diameter of 8 inches
natita [175]

Hello there!

We are going to follow the volume of a sphere since a volleyball is a sphere. V=4/3πr^3 is the formula for finding the volume of a sphere. The only unknown value is r, or the radius. We find the radius by halving the diameter.

8/2 = 4, so we have a radius of 4 inches.

Place the value of 4 in for r - V = 4/3 x π x (4)^3

Now solve.

V = 4/3 x π x (4)^3

Start by squaring 4.

V = 4/3 x π x 64

Next, multiply 4/3 by 64. (<em>you can do it in any order since there are no parenthesis</em>)

V = π x 85.33

Lastly, multiply 85.33 by pi.

V = 268.08

So, your answer is approximately 268.08, since we used rounding it is not exact. I hope this was helpful and have a great rest of your day! :)

8 0
3 years ago
What are the mean, median, and mode of the following data set? 3/4 2/5 1/10 3/4 1/4 a. mean: 1/10, median: 1/10, mode: 3/4 b. me
steposvetlana [31]
Mean: 9/20
Mode: 3/4 
Median: 2/4
3 0
3 years ago
Read 2 more answers
Makayla and ember went shopping for clothes and spent 262.00 if the tax rate is 5% what is Makayla and ember’s total after tax?
Serjik [45]

262.00*1.05= $275.10

7 0
3 years ago
Read 2 more answers
Two candidates are randomly selected. a. List all the possible outcomes. b. What is the probability that both are qualified? c.
steposvetlana [31]

Question:

Four candidates are to be interviewed for a job. Two of them, numbered 1 and 2, are qualified, and the other two, numbered 3 and 4, are not.

Answer:

a. S = {12,13,14,23,24,34}

b. 1/6

c. ⅔

Step-by-step explanation:

Let S = Sample Space i.e. total possible outcomes

Given that candidates 1 and 2 are qualified and 3 and 4 are not qualified.

If two candidates are randomly selected. The list of all possible outcomes is as follows

S:{12,13,14,23,24,34}

And the number of outcomes is 6

b. What is the probability that both are qualified?

The event that both are qualified is given as {12} or {21}

From the sample space in (a) above, there's only one occurrence of {12} = 1

So, the probability is calculated as 1/6

c. What is the probability that exactly one is qualified?

The event that one one is qualified is given as {13,14,23,24}

Total = 4

Probability = 4/6

Probability = ⅔

5 0
3 years ago
I need help pleaseeee!!!!! I don’t understand
olganol [36]

Answer:

a. x = 5, m∠FGH = 22°

b. m∠HGI = 22°

c.  m∠FGI = 44°

Step-by-step explanation:

Since GH bisects FGI this means it divides the angle in two equal parts.

a. solving for x means equating them:

5x-3 = 6x-8 =>

5x - 6x = 3 - 8 =>

x = 5.

Both m∠FGH and m∠HGI are 5*5-3 = 22°

c. Add both angles: m∠FGH + m∠HGI = 44°

8 0
3 years ago
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