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3 years ago

14

2.One slice of cheese pizza contains 290 calories. A medium-size orange has one fifth that number of calories. How many calories

are in a medium-size orange?

1 answer:

natta225 [31]3 years ago

4 0

58 cal in the orange

290÷5 is 58

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The probability of a spinner landing on a 4 is 5/8. What is the probability that the spinner will land on a number other than 4?

Alja [10]

The probability that it doesn't land on 4 would be 3/8. This is because theres a 5/8 chance it lands on 4 so just do the opposite which would be 3/8.

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3 years ago

-3x - y = 15<br> y = -8x<br> (x, y) = (0<br> )<br> 9,0

Nataly [62]

<h3>The solution is (x, y) = (3, -24)</h3>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

-3x - y = 15 -------- eqn 1

y = -8x ------ eqn 2

We have to find solution of (x, y)

We can solve by substitution method

<em><u>Substitute eqn 2 in eqn 1</u></em>

-3x - (-8x) = 15

-3x + 8x = 15

5x = 15

Divide both sides by 5

<h3>x = 3</h3>

Substitute x = 3 in eqn 2

y = -8(3)

<h3>y = -24</h3>

Thus solution is (x, y) = (3, -24)

4 0

3 years ago

Karan needs to choose between two gym plans. He can either pay a $150 joining fee and a $10 monthly fee, or he can pay a $50 joi

Ierofanga [76]

Let x be the month on which the fee for two plans are equal.

Therefore,

150 + 10x = 50 + 30x

10x - 30x = 50 - 150

-20x = -100

x = 5

Cumulative cost = 150 + 10(5)

= 150 + 50

= 200

Hence, Karan will pay a cumulative cost of $200 dollars with either plan to go to the gym for 5 months.

4 0

3 years ago

Se golpea (chuta) un balón sobre el piso y sale dando botes parabólicos cada vez menores. Si se lanzo inicialmente con una veloc

Ipatiy [6.2K]

Answer:

a)d = 180,91 m

b)t = 11,76 seg

Step-by-step explanation:

Para el lanzamiento de proyectil, la ecuación que nos da la velocidad en V(y) es:

V(y) = Voy - g*t

en donde Voy = Vo * senα ( donde Vo es la velocidad inicial, α el angulo del disparo.

Si en esta ecuación hacemos V(y) = 0 estamos en el punto donde el componente en el eje y de la velocidad del proyectil es cero, ese punto es el punto medio del recorrido.

0 = Vo*sen 60⁰ - g*t

g*t = Vo* √3/2

t = { 32 [m/s] * √3 }2*9,8 [m/s²]

t = 16*√3 / 9,8

t = 2,8278 seg

El tiempo total del primer recorrido es entonces por simetría

t₁ = 2 * 2,8278 t₁ = 5,6556 seg

La distancia del primer impacto al suelo es:

x = Vox * t₁ ( Vox es constante Vx = Vo*cos 60⁰ )

x = 32 * (1/2) * 5,6556

x₁ = 90,49 m

Aplicando los mismos criterios ahora para el segundo bote

Ahora Vo = 32 - 32*(1/4)

V = 24 m/s

g*t = 24 * sen 50⁰

t = 24* 0,7660/ 9,8

t = 1,8759

2*t = 2*1,8759

t₂ = 3,7518 seg

x₂ = Vox * t₂

x₂ = 24* 0,6428*3,7518

x₂ = 57,88 m

Y para el tercer bote Vo = 24 - 24(1/4) Vo = 18 m/s α = 40⁰

t = 18 *0,6428/9,8

t = 1,18

2t = t₃ = 2*1,18

t₃ = 2,36 seg

x₃ = Vox * 2,36 Vox = Vo*cos 40 Vox = 18*0,7660

Vox = 13,79

x₃ = 13,79*2,36

x₃ = 32,54 m

La distancia total será

d = x₁ + x₂ + x₃

d = 90,49 + 57,88 + 32,54

d = 180,91 m

y el tiempo total será la suma de los tiempos

t = t₁ + t₂ + t₃

t = 5,65 + 3,75 + 2,36

t = 11,76 seg

8 0

3 years ago

Daily high temperatures in St. Louis for the last week were as follows: 95, 92, 93, 92, 95, 90, 90 (yesterday). a) The

hichkok12 [17]

Answer:

a) T = 91.7 degrees

b) T = 90 degrees

c) MAD = 1.9

d) MSE = 5.05

Step-by-step explanation:

Given:

- Daily high temperatures in St. Louis for the last week were as follows:

95, 92, 93, 92, 95, 90, 90

Find:

a) Forecast the high temperature today, using a 3-day moving average.

b) Forecast the high temperature today, using a 2-day moving average.

c) Calculate the mean absolute deviation based on a 2-day moving average, covering all days in which you can have a forecast and an actual temperature.

d) The mean squared error for the 2-day moving average

Solution:

a)

- The set of 3 day moving average is as follows:

4. (95 + 92 + 93) ÷ 3 = 93.33⁰C

5. (92 + 93 + 92) ÷ 3 = 92.33⁰C

6. (93 + 92 + 95) ÷ 3 = 93.33⁰C

7. (92 + 95 + 90) ÷ 3 = 92.33⁰C

8. (95 + 90 + 90) ÷ 3 = 91.667⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 91.7 degrees

b)

- The set of 2 day moving average is as follows:

3. (95 + 92) ÷ 2 = 93.5⁰C

4. (95 + 93) ÷ 2 = 92.5⁰C

5. (93 + 92) ÷ 2 = 92.5⁰C

6. (92 + 95) ÷ 2 = 93.5⁰C

7. (95 + 90) ÷ 2 = 92.5⁰C

8. (90 + 90) ÷ 2 = 90⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 90 degrees

c)

Error Error^2

3. 93.5⁰C 0.5 0.25

4. 92.5⁰C 0.5 0.25

5. 92.5⁰C 2.5 6.25

6. 93.5⁰C 3.5 12.25

7. 92.5⁰C 2.5 6.25

8. 90⁰C

- The mean absolute deviation as follows:

MAD = Sum of all errors / 5

MAD = (0.5+0.5+2.5+3.5+2.5) / 5

MAD = 1.9

d)

- The mean squared error deviation as follows:

MSE = Sum of all error^2 / 5

MSE = (0.25+0.25+6.25+12.25+6.25) / 5

MSE = 5.05

4 0

3 years ago