In the diagram below, what is the approximate length of the minor arc DE?
1 answer:
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Answer:
<u>640 pounds </u>
Step-by-step explanation:
The rest of the question is the attached figure
So, the total volume = V(cylinder ) + V(cone)
The volume of cylinder = π r² h
The volume of cone = π r² h/3
Both of the cylinder and the cone have the same diameter = 14 inches
So, the radius = 14/2 = 7 inches
The height of the cylinder is 13 inches and the height of the cone is 9 inches.
So, The volume of cylinder = π r² h = π * 7² * 13 = 2,001.2 in³
And The volume of cone = π r² h/3 = π * 7² * 9/3 = 461.8 in³
So, the total volume = 2,001.2 + 461.8 = 2,463 in³
So, the total weight = 0.26 pounds per cubic inch times the total volume
= 0.26 * 2463 = 640.38 pounds
= <u>640 pounds (to the nearest pound)</u>
