Answer:
Use the distance formula on both points AC and AB.
<em>Distance formula is this</em><em>:</em>
<em>\begin{gathered}d=\sqrt{(x2-x1)^2+(y2-y1)^2} \\\\d=\sqrt{(1--5)^2+(8--7)^2} \\\\d=\sqrt{(6)^2+(15)^2} \\\\d=\sqrt{36+225} \\\\d=\sqrt{261} \\\\\end{gathered}d=(x2−x1)2+(y2−y1)2d=(1−−5)2+(8−−7)2d=(6)2+(15)2d=36+225d=261</em>
Distance for AC is 16.16
Now do the same with the numbers for AB and get the distance of 5.39
2. To get the area, use the formula 1/2 x base x height
AB is the base and AC is the height.
1/2 x 16.16 x 5.39 = 43.55
the answer is 43.5
Step-by-step explanation:
7h + 4 > 5 - 5h
7h + 5h > 5 - 4
12h > 1
h > 1/12
8 ÷ 0.001 = 8 000
a) 8 ÷ 0.0001 = 80 000
8 ÷ 0.001 = 8 000
b) 8 ÷ 0.01 = 800
8 ÷ 0.001 = 8 000
8 ÷ 1/10 = 8 ÷ 0.1 = 80
c)8 ÷ 0.01 = 8 000
9514 1404 393
Answer:
58
Step-by-step explanation:
The marked points on the graph show that the number of hot cocoas sold decreases by 6 when the temperature goes up by 6 degrees. That is, the line has a slope of -1. The y-intercept is 100, so the equation of the line can be written as ...
y = mx +b . . . . . line with slope m and y-intercept b
y = -x +100
Then for x = 42, the expected value of y is ...
y = -42 +100 = 58
Mei Mei can expect to sell 58 hot cocoas on a day when the high is 42°F.
Answer:
C because h is increasing at -0.5,3
