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Oksanka [162]
2 years ago
7

CAN ANYONE HELP ANSWER THIS

Mathematics
1 answer:
bija089 [108]2 years ago
5 0

9514 1404 393

Answer:

  58

Step-by-step explanation:

The marked points on the graph show that the number of hot cocoas sold decreases by 6 when the temperature goes up by 6 degrees. That is, the line has a slope of -1. The y-intercept is 100, so the equation of the line can be written as ...

  y = mx +b . . . . . line with slope m and y-intercept b

  y = -x +100

Then for x = 42, the expected value of y is ...

  y = -42 +100 = 58

Mei Mei can expect to sell 58 hot cocoas on a day when the high is 42°F.

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A multiple choice quiz has two questions , each with five answer choices. Only one choice is correct. Find the probability of an
Leokris [45]

Answer:

1/25 to get both correct

Step-by-step explanation:

So the probability of getting one choice correct is 1/5

Since 5 choices 1 is correct

now we have to get 2 in a row correct so

1/5*1/5=1/25

4 0
2 years ago
Simplify (x^-2y^6/x^-4y^8)1/2
AlexFokin [52]
Simplify the following:
(y^6 y^8)/((2 x^2)/(x^4))
Combine powers. (y^6 y^8)/((x^2×2)/x^4) = (y^(8 + 6) x^(4 - 2))/2:
(y^(8 + 6) x^(4 - 2))/2
8 + 6 = 14:
(y^14 x^(4 - 2))/2
4 - 2 = 2:
Answer: (y^14 x^2)/2
6 0
3 years ago
. upper left chamber is enlarged, the risk of heart problems is increased. The paper "Left Atrial Size Increases with Body Mass
Sonbull [250]

Answer:

Part 1

(a) 0.28434

(b) 0.43441

(c) 29.9 mm

Part 2

(a) 0.97722

Step-by-step explanation:

There are two questions here. We'll break them into two.

Part 1.

This is a normal distribution problem healthy children having the size of their left atrial diameters normally distributed with

Mean = μ = 26.4 mm

Standard deviation = σ = 4.2 mm

a) proportion of healthy children have left atrial diameters less than 24 mm

P(x < 24)

We first normalize/standardize 24 mm

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (24 - 26.4)/4.2 = -0.57

The required probability

P(x < 24) = P(z < -0.57)

We'll use data from the normal probability table for these probabilities

P(x < 24) = P(z < -0.57) = 0.28434

b) proportion of healthy children have left atrial diameters between 25 and 30 mm

P(25 < x < 30)

We first normalize/standardize 25 mm and 30 mm

For 25 mm

z = (x - μ)/σ = (25 - 26.4)/4.2 = -0.33

For 30 mm

z = (x - μ)/σ = (30 - 26.4)/4.2 = 0.86

The required probability

P(25 < x < 30) = P(-0.33 < z < 0.86)

We'll use data from the normal probability table for these probabilities

P(25 < x < 30) = P(-0.33 < z < 0.86)

= P(z < 0.86) - P(z < -0.33)

= 0.80511 - 0.37070 = 0.43441

c) For healthy children, what is the value for which only about 20% have a larger left atrial diameter.

Let the value be x' and its z-score be z'

P(x > x') = P(z > z') = 20% = 0.20

P(z > z') = 1 - P(z ≤ z') = 0.20

P(z ≤ z') = 0.80

Using normal distribution tables

z' = 0.842

z' = (x' - μ)/σ

0.842 = (x' - 26.4)/4.2

x' = 29.9364 = 29.9 mm

Part 2

Population mean = μ = 65 mm

Population Standard deviation = σ = 5 mm

The central limit theory explains that the sampling distribution extracted from this distribution will approximate a normal distribution with

Sample mean = Population mean

¯x = μₓ = μ = 65 mm

Standard deviation of the distribution of sample means = σₓ = (σ/√n)

where n = Sample size = 100

σₓ = (5/√100) = 0.5 mm

So, probability that the sample mean distance ¯x for these 100 will be between 64 and 67 mm = P(64 < x < 67)

We first normalize/standardize 64 mm and 67 mm

For 64 mm

z = (x - μ)/σ = (64 - 65)/0.5 = -2.00

For 67 mm

z = (x - μ)/σ = (67 - 65)/0.5 = 4.00

The required probability

P(64 < x < 67) = P(-2.00 < z < 4.00)

We'll use data from the normal probability table for these probabilities

P(64 < x < 67) = P(-2.00 < z < 4.00)

= P(z < 4.00) - P(z < -2.00)

= 0.99997 - 0.02275 = 0.97722

Hope this Helps!!!

7 0
3 years ago
Holly drove 100 miles in 4 hours, and Yemi drove 100 miles in 5 hours. How can you compare the speeds of Holly and Yemi? Explain
Lelu [443]
The first thing that yo do is divide 100 by 5 for Yemi and that's how fast she drove which is 20 miles per hour. And then you do the same thing for Holly 100 divided by 4 which is 25 mph. So Holly is driving faster than Yemi. So you can compare them by dividing the miles by hours for both of them.
3 0
3 years ago
5.241 divided by 3 please help me​
SOVA2 [1]

Hey Mate!

Your answer is

1.747

Tell me if this helps!<3

5 0
3 years ago
Read 2 more answers
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