Answer:
Step-by-step explanation:
Was like why you tryna I wanna know that I
Answer:
1/3 is your answer
Step-by-step explanation:
hcjiiii suck
is continuous on [0, 4] and differentiable on (0, 4), so the MVT holds. We have
![f'(x)=\dfrac1{\sqrt x}](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Cdfrac1%7B%5Csqrt%20x%7D)
so that by the MVT, there is some
such that
![f'(c)=\dfrac{f(4)-f(0)}{4-0}\implies\dfrac1{\sqrt c}=\dfrac{2\sqrt4}4=1](https://tex.z-dn.net/?f=f%27%28c%29%3D%5Cdfrac%7Bf%284%29-f%280%29%7D%7B4-0%7D%5Cimplies%5Cdfrac1%7B%5Csqrt%20c%7D%3D%5Cdfrac%7B2%5Csqrt4%7D4%3D1)
![\implies1=\sqrt c\implies \boxed{c=1}](https://tex.z-dn.net/?f=%5Cimplies1%3D%5Csqrt%20c%5Cimplies%20%5Cboxed%7Bc%3D1%7D)
Using trial and error
x^4+5x^2-36 factors to (x-2)(x+2)(x^2+9)
2x^2+9x-5 factors to (x+5)(2x-1)
so
(x-2)(x+2)(x^2+9)(x+5)(2x-1)=0
set each to zero
x-2=0
x=2
x+2=0
x=-2
x^2+9=0
x^2=-9
x=3√-1
x=3i
x+5=0
x=-5
2x-1=0
2x=1
x=1/2=0.5
roots are
x=-5-2,0.5,2, and the imaginary root 3i
Answer:
I Think its fed
Step-by-step explanation: