Answer:
(5 - y) ^3 = 125 - 75y + 15y^2 - y^3
Step-by-step explanation:
Binomial expression
1
1. 1
1. 2. 1
1. 3. 3. 1 --------power of 3
( 5 - y) ^3
( 5 - y) (5 - y) (5 - y)
( a + b) ^3 = a^3 + 3a^2b + 3ab^2 + b^3
a = 5
b = -y
( 5 - y) ^2 = ( 5 - y) (5 - y)
= 5( 5 - y) - y(5 - y)
= 25 - 5y - 5y + y^2
=(25-10y+y^2)
( 25 - 10y + y^2)( 5 - y)
= 5(25 - 10y + y^2) - y( 25 - 10y + y^2)
= 125 - 50y + 5y^2 - 25y + 10y^2 - y^3
Collect the like terms
= 125 - 50y - 25y + 5y^2 + 10y^2 - y^3
= 125 - 75y + 15y^2 - y^3
Answer:
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Answer:
It is irrational because it can not be represented as a fraction of two integers
Step-by-step explanation:
Given
![H = \sqrt[3]5](https://tex.z-dn.net/?f=H%20%3D%20%5Csqrt%5B3%5D5)
Required
Why is the area irrational?
First, we need to calculate the area
![Area = \frac{1}{2}(3.6 + 12\frac{1}{3}) * \sqrt[3]5](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7B1%7D%7B2%7D%283.6%20%2B%2012%5Cfrac%7B1%7D%7B3%7D%29%20%2A%20%5Csqrt%5B3%5D5)
<em>It is irrational because it can not be represented as a fraction of two integers</em>
Always add them all around and then divide the two and you should get the correct answer
Answer:
1/3
Step-by-step explanation:
Range of data set: 12 - 6 = 6
Given that there is a uniform distribution:
P(6<x<7) = 1/6
P(7<x<8) = 1/6
P(8<x<9) = 1/6
P(9<x<10) = 1/6
P(10<x<11) = 1/6
P(11<x<12) = 1/6
where x is weight loss
Probability that weight loss is more than 10 pounds:
P(10<x<11) + P(11<x<12) = 1/6 + 1/6 = 1/3
