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slavikrds [6]
4 years ago
6

there are approximately 4021/4 meters around a typical running track sandra has challenged herself to run 10 maps a day for 5 da

ys how many meters will sandra run is she meets her challenge
Mathematics
1 answer:
Lostsunrise [7]4 years ago
5 0

Total distance of a typical running track  = 402 \frac{1}{4} meters.

Let us convert it into impoerper fraction first, we get

\frac{402\times4+1}{4}=\frac{1609}{4}meters.

Total number of maps in a day = 10 maps.

Number of days of running = 5 days.

Total number of maps of 5 days = 10 × 5 = 50 maps.

Total number of meters in 50 maps = 50\times\frac{1609}{4}=\frac{80450}{4}=20112\frac{1}{2}\ meters..

<h2>Therefore,  20112\frac{1}{2}\ meters will sandra run is she meets her challenge</h2>
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4 0
3 years ago
Y=2x-5<br> 3x+8y+32=56 <br> What does y and x equal?
AVprozaik [17]
Y = 2x - 5
3x + 8y + 32 = 56
3x + 8(2x - 5) + 32 = 56
3x + 8(2x) - 8(5) + 32 = 56
3x + 16x - 40 + 32 = 56
19x - 8 = 56
<u>      + 8   + 8</u>
     <u>19x</u> = <u>64</u>
      19     19
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y = 2(3.4) - 5
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5 0
3 years ago
The quadrilateral shown is rotated 90° clockwise about the origin. In which quadrant is the image of the quadrilateral located?
Viktor [21]

Answer:

Option (2). 1

Step-by-step explanation:

Coordinates of point A, B, C and D are,

A(-4, 4), B(-2, 4), C(-2, 1) and D(-4, 3).

Quadrilateral ABCD when rotated 90° clockwise about the origin,

Rule for the rotation of the vertices,

(x, y) → (y, -x)

Following the rule of rotation coordinates of the image points,

A(-4, 4) → A'(4, 4)

B(-2, 4) → B'(4, 2)

C(-2, 1) → C'(1, 2)

D(-4, 3) → D'(3, 4)

Since all image points have the positive coordinates (x and y coordinates), image quadrilateral A'B'C'D' will be located in 1st quadrant.

Option (2) is the correct option.

4 0
3 years ago
Help ASAP In a system of linear equations the two equations have the same slope. Describe the possible solutions to this equatio
Troyanec [42]

Answer:

If the two linear equations have the same slope, the equations represent the same line. Since a line intersects with itself everywhere, there will be an infinite number of solutions.

6 0
3 years ago
a climber starts descending from 504 feet above sea level and keeps going until she gets to 40 feet below sea level, how may fee
GenaCL600 [577]

Answer:

544 feet.

Step-by-step explanation:

|504| +|-40|=544

8 0
3 years ago
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