Answer:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs
31 hope that helps have a good one
Answer:
He collected 180 other stamps
Step-by-step explanation:
Sorry if it's wrong
djdhdhusidhdushdhd
Carryonlearning <3
The number of subsets of a set is 256, and the number of subsets of a set is 128. If | ∪ | = 2 × | ∩ |, then what is the value of | ∩ |? and what will be the number of subsets of the set ∩ ?
Answer:
42
Step-by-step explanation:
for one cup 28/12
for 18 cup,
(28/12)×18
=42
