Answer:
The equation of the perpendicular line would be y = -2/5x - 1
Step-by-step explanation:
In order to find this line, we must first find the slope of the original line. We do this by solving for y.
-5x + 2y = -10
2y = 5x - 10
y = 5/2x - 5
This shows us a slope of 5/2. TO find the perpendicular slope, we use the opposite and reciprocal. This means we negative 5/2 to get -5/2 and then we flip it to get -2/5. Now that we have this, we can use the slope and the point in point-slope form to get the equation.
y - y1 = m(x - x1)
y - 1 = -2/5(x + 5)
y - 1 = -2/5x - 2
y = -2/5x - 1
Answer:
C) 37
Step-by-step explanation:
1/2(PQ)=RQ
2.5x+17=6x-11
17=3.5x-11
28=3.5x
x=8
RQ=6(8)-11
RQ=48-11
RQ=37
There a absolute value so mark out the negative and 25 / by 16 is 1 so 1 is your answer if you really do the problem on paper
Answer:
tan(2u)=[4sqrt(21)]/[17]
Step-by-step explanation:
Let u=arcsin(0.4)
tan(2u)=sin(2u)/cos(2u)
tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]
If u=arcsin(0.4), then sin(u)=0.4
By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.
This also implies cos(u)=sqrt(0.84) since cosine is positive.
Plug in values:
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]
tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]
tan(2u)=[(40)(sqrt(0.84)]/[34]
tan(2u)=[(20)(sqrt(0.84)]/[17]
Note:
0.84=0.04(21)
So the principal square root of 0.04 is 0.2
Sqrt(0.84)=0.2sqrt(21).
tan(2u)=[(20)(0.2)(sqrt(21)]/[17]
tan(2u)=[(20)(2)sqrt(21)]/[170]
tan(2u)=[(2)(2)sqrt(21)]/[17]
tan(2u)=[4sqrt(21)]/[17]
