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Vesna [10]
3 years ago
15

If f(×)=4×^2+1 and g(x)=×^2-5 find (f-g)(×)​

Mathematics
1 answer:
trasher [3.6K]3 years ago
8 0

Answer:

\large\boxed{(f-g)(x)=3x^2+6}

Step-by-step explanation:

(f-g)(x)=f(x)-g(x)\\\\f(x)=4x^2+1,\ g(x)=x^2-5\\\\\text{Substitute:}\\\\(f-g)(x)=(4x^2+1)-(x^2-5)=4x^2+1-x^2-(-5)\\\\=4x^2+1-x^2+5\qquad\text{combine like terms}\\\\=(4x^2-x^2)+(1+5)=3x^2+6

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You need to cover the playground of a child development center with mulch. the playground is 125 feet long and 60 feet wide. you
kirill [66]
The answer is 139 cubic yards

This mulch will be of cylindrical shape.
The volume (V) of a cylinder is: 
V = l · w · h           (l - length, w - width, h - height (in our example, height = depth)

It is known:
l = 125 feet
w = 60 feet
h = 6 inches = 0.5 feet

V = l · w · h = 125 · 60 · 0.5 = 3750 feet³

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4 0
3 years ago
2. A square-based tent has the cross-sectional
ollegr [7]

(a) Length of the height is 2.732 m

(b) Length of the base is 5.466 m

<u>Explanation:</u>

An image is attached for reference.

(a)

In ΔAOB,

sin 30^o = \frac{AO}{AB} \\\\0.5 = \frac{AO}{2} \\\\AO = 1 m

In ΔBGD,

sin 60^o = \frac{BG}{BD} \\\\0.866 = \frac{BG}{2} \\\\BG = 1.732 m

According to the figure, BG = OE = 1.732 m

Height of the tent, AE = AO + OE

                                  = 1 m + 1.732 m

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(b)

DF = ?

In ΔAOB,

tan 30^o = \frac{AO}{OB} \\\\0.577 = \frac{1}{OB} \\\\OB = 1.733 m\\\\\\

According to the figure, OB = GE = 1.733 m

In ΔBGD,

tan 60^o = \frac{BG}{DG} \\\\1.732 = \frac{1.732}{DG}\\ \\DG = 1m

According to the figure, DE = DG + GE

                                      DE = 1 m + 1.733 m

                                     DE = 2.733 m

Length of the base, DF = 2 X DE

                              DF = 2 X 2.733 m

                               DF = 5.466 m

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