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3 years ago

If f(×)=4×^2+1 and g(x)=×^2-5 find (f-g)(×)

Mathematics

1 answer:

trasher [3.6K]3 years ago

8 0

Answer:

$\large\boxed{(f-g)(x)=3x^2+6}$

Step-by-step explanation:

$(f-g)(x)=f(x)-g(x)\\\\f(x)=4x^2+1,\ g(x)=x^2-5\\\\\text{Substitute:}\\\\(f-g)(x)=(4x^2+1)-(x^2-5)=4x^2+1-x^2-(-5)\\\\=4x^2+1-x^2+5\qquad\text{combine like terms}\\\\=(4x^2-x^2)+(1+5)=3x^2+6$

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4 years ago

A square has a perimeter of 8 cm. What is its area?

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A square has four sides which all have the same length.

So if we call the length of each side of the square 'a'

The sum of length of all the sides (the perimeter) will be ,

a + a + a + a = 4a

Now let's equal this to the perimeter to find the length of each side 'a'

$4a\quad =\quad 8\\ \\ a\quad =\quad \frac { 8 }{ 4 } \\ \\ a\quad =\quad 2$

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The answer :

$\boxed { 4\quad c{ m }^{ 2 } }$

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4 years ago

Read 2 more answers

If f(×)=4×^2+1 and g(x)=×^2-5 find (f-g)(×)​

If f(×)=4×^2+1 and g(x)=×^2-5 find (f-g)(×)