The first term will be 3 and the sum of the first 9 terms will be 81.
<h3>What is Arithmetic progression?</h3>
The difference between every two successive terms in a sequence is the same this is known as an arithmetic progression (AP).
The arithmetic progression has wider use in mathematics for example sum of natural numbers.
Natural number = 1,2,3,4,5,6,7,8...
Given,
Six terms as 10.5
So,
a₆ = 10.5
Common difference(d) = 1.5
The nth term of an AP is given by
= a + (n-1)d
So,
a₆ = a + (6-1)d
10.5 = a + 5(1.5)
a = 3
Now,
The Sum of n terms is given by
S = n/2[2a + (n-1)d]
S = 9/2[6 + 8(1.5)]
S = 81
Hence the first term will be 3 and the sum of 9 terms will be 81.
For more about Arithmetic progression
brainly.com/question/20385181
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One is negative and the other is positive and one has a whole number, and the other only has a decimal
Answer:
Advance tickets=$25
Same-day tickets=$15
Step-by-step explanation:
Complete question below:
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $ 40. For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1075 . What was the price of each kind of ticket?
Let
advance tickets=x
Same-day tickets=y
Combined cost of advance and same-day tickets=$40
It means,
x+y=40 Equ (1)
25 advance tickets and 30 same-day tickets=$1075
It means,
25x+30y=1075 Equ(2)
From (1)
x+y=40
x=40-y
Substitute x=40-y into (2)
25x+30y=1075
25(40-y)+30y=1075
1000-25y+30y=1075
5y=1075-1000
5y=75
Divide both sides by 5
5y/5=75/5
y=15
Recall,
x+y=40
x+15=40
x=40-15
=25
x=25
Advance tickets=$25
Same-day tickets=$15
Check
25x+30y=1075
25(25)+30(15)=1075
625+450=1075
1075=1075
