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4 years ago

14

Consider the three points (-7,-7), (21,14), (49,35)

1 answer:

kykrilka [37]4 years ago

6 0

E is the correct answer

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For how many weeks would the class need to have car washes to earn $5000.

nikdorinn [45]

The correct answer would be for 29 weeks.
Its because if for 4 weeks the profit is $700, divide 700 and 4 which gives you $175 per week. Then divide 5000 and 175 which gives you 28.5714286. So all you have to do is round it up to the nearest whole which gives you the answer: 29 weeks.
Hope that helps. :)

5 0

4 years ago

Find the area of the isosceles triangle.

kogti [31]

Answer:

The hight length : h

The base length : a

Apply the Pythagorean theorem in the right triangle :

h² = 13² - (10/2) = 144

h = √144 = 12 cm

S = (a x h)/ 2 = ( 10 x 12 )/2 = 60 cm²

Step-by-step explanation:

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3 years ago

13. What values of x satisfy the inequality 4x + 2 > 10? *<br> What is the answer

mojhsa [17]

Answer:

Hi! The answer to your question is x > 2

Step-by-step explanation:

☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆

☆Brainliest is greatly appreciated!☆

Hope this helps!!

- Brooklynn Deka

4 0

3 years ago

Read 2 more answers

In the Metric System: As you move from a smaller unit to a larger unit, the number of larger units required will be LESS. Theref

3241004551 [841]

Answer:

True

Step-by-step explanation:

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3 years ago

Read 2 more answers

The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

Anettt [7]

Answer:

a. $\frac{1}{15}$

b. $\frac{2}{5}$

c. $\frac{14}{15}$

d. $\frac{8}{15}$

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

a. Favorable cases for Both the laptops to be selected = $_2C_2$ = 1

Total number of cases = 15

Required probability is $\frac{1}{15}$ .

b. Favorable cases for both the desktop machines selected = $_4C_2=6$

Total number of cases = 15

Required probability is $\frac{6}{15} = \frac{2}{5}$ .

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

2. Both desktop:

Favorable cases = $_4C_2=6$

Total number of favorable cases = 8 + 6 = 14

Required probability is $\frac{14}{15}$ .

d. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

Total number of cases = 15

Required probability is $\frac{8}{15}$ .

8 0

4 years ago