Answer:
here
Step-by-step explanation:
We have been given that, in a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays and we have to find the probability of not hitting boundary. So, the probability of hitting boundary⇒Number of boundaries hitTotal number of balls=630=15.
<u>Answer</u>
14 4/9
<u>Turn 9 2/3 into an Improper Fraction</u>
Multiply 9*3 and get 27. Now add 2 and get 29 (Denominator stays the same)
9 2/3 = 29/3
<u>Turn 4 7/9 into an Improper Fraction</u>
Multiply 4*9 and get 36. Now add 7 and get 43 (Denominator stays the same)
4 7/9 = 43/9
<u>Add</u>
29/3 + 43/9 = 130/9
<u>Turn 130/9 into a Mixed Number (Divide)</u>
130/9 = 14 4/9
Hope This Helps!
Answer:
6x
Step-by-step explanation:
because in front of x^3 there is 6x and also the qn has asked to find the coefficient of x^3
451.76 and <span>451.7576 these two</span>
The answers are
f
o
g
(
x
)
=
−
2
x
+
23
and
g
o
f
(
x
)
=
−
2
x
+
5
Explanation:
f
(
x
)
=
−
2
x
+
11
g
(
x
)
=
x
−
6
f
o
g
(
x
)
=
f
(
g
(
x
)
)
=
f
(
x
−
6
)
=
−
2
(
x
−
6
)
+
11
=
−
2
x
+
12
+
11
=
−
2
x
+
23
g
o
f
(
x
)
=
g
(
f
(
x
)
)
=
g
(
−
2
x
+
11
)
=
−
2
x
+
11
−
6
=
−
2
x
+
5
I think that the equations speak by themselves.
Of course,
f
o
g
(
x
)
≠
g
o
f
(
x
)
