Answer:
1716 ways
Step-by-step explanation:
Given that :
Number of entrants = 13
The number of ways of attaining first, second and third position :
The number of ways of attaining first ; only 1 person can be first ;
Using permutation :
nPr = n! ÷(n-r)!
13P1 = 13! ÷ 12! = 13
Second position :
We have 12 entrants left :
nPr = n! ÷(n-r)!
12P1 = 12! ÷ 11! = 12
Third position :
We have 11 entrants left :
nPr = n! ÷(n-r)!
11P1 = 11! ÷ 10! = 11
Hence, Number of ways = (13 * 12 * 11) = 1716 ways
Answer:
60
Step-by-step explanation:
when you multiply 100 by .6 it equals 60
<h2>B</h2><h2>C</h2><h2>E</h2><h2></h2><h3>are the correct answers!</h3><h3></h3><h3></h3><h3></h3><h3></h3><h3></h3><h3><em>Let me know if I'm wrong!</em></h3>
Answer:
C
Step-by-step explanation:
The technical probability of rolling any number on a standard die is 1/6 because there's six numbers. Based on that, since he rolled a "4" on 5 tosses, it seems likely that it's 30 times, because 1/6 of 30 is 5. I haven't done probability in awhile but if I remember correctly that should be right
Answer:
PR = 16
SR = 12
Step-by-step explanation:
6/8 = (x-3)/(x+1)
8x-24 = 6x+6
simplify
2x = 30
x = 15
PR = 15 + 1 = 16
SR = 15 - 3 = 12