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MariettaO [177]
3 years ago
13

Evaluate |5 - 15|. -10 10 20 -20

Mathematics
2 answers:
Neko [114]3 years ago
6 0

Answer:

10

Step-by-step explanation:

The absolute value always returns a positive value, that is

| - a | = | a | = a , thus

| 5 - 15 | = | - 10 | = 10

Marianna [84]3 years ago
4 0

It's pretty simple! The answer is 10! Because the absolute value of a number is never negative.

(Mark me as the brainliest if my answer is helpful!)

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Evaluate the following expression when x = 6 and y = 2:
Liula [17]

Answer:

11/2

Step-by-step explanation:

\frac{ {x}^{2} +  {y}^{3}  }{2 + x}  \\

when,

x = 6 \\ y = 2

Now substitute the value we get,

\frac{ {6}^{2}  +  {2}^{3} }{2 + 6} \\  \\  =  \frac{36 + 8}{8}   \\  \\  =  \frac{44}{8} \\  \\  =  \frac{11}{2}

5 0
3 years ago
Which graph represents the inequality y-2x≤1?
Furkat [3]

y ≤ 1 + 2x is the answer

5 0
3 years ago
HELP Trigonometry: Find the area of each shape using the given information
rjkz [21]

Given:

The vertical height of the trapezoid = 2.9 m

The bases of the trapezoid are 2.3 m and 9.3 m.

To find:

The area of the given trapezoid.

Solution:

The area of a trapezoid is:

A=\dfrac{1}{2}(a+b)h

Where, a, b are bases or length of parallel sides and h is the vertical height of the trapezoid.

Putting a=2.3,\ b=9.3,\ h=2.9 in the above formula, we get

A=\dfrac{1}{2}(2.3+9.3)(2.9)

A=\dfrac{1}{2}(11.6)(2.9)

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Therefore, the area of the given trapezoid is 16.82 square m.

6 0
3 years ago
5. Prove that opposite angles of a cyclic quadrilateral are supplementary.
Temka [501]

Answer:

See attached for the cyclic quadrilateral

To prove: <BAD + <BCD =180°

Construction: Join B and D to the centre O of circle ABCD

Proof  

With the lettering of the attached drawing,

                         <BOD = 2y    (angle at centre is 2 X angle at circumference)

            Reflex <BOD   = 2x     (angle at centre is 2 X angle at circumference)

                    ∴ 2x + 2y = 360°    (angle at point)

                       ∴ x + y   = 180°                    

       ∴ <BAD + <BCD   = 180°            

Step-by-step explanation:

The vertices of a cyclic quadrilateral lie on the circumference of the circle and the opposite angles of a cyclic quadrilateral lie in opposite segment of a circle.

The question is to prove that the opposite angles of a cyclic quadrilateral are supplementary that is 180°. Another way of stating this theory is 'Angles in opposite segments are supplementary'.

Note that the sum of supplementary angles is 180°.

3 0
3 years ago
What is 7/11 equivalent to
Sonbull [250]

Answer:

308 ? Good luck

Step-by-step explanation:

5 0
3 years ago
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