All categories

4 years ago

Answer please for 15pts

Mathematics

1 answer:

Dennis_Churaev [7]4 years ago

5 0

Simplify the equation

√363 becomes 11 √3

3 √27 becomes 9 √3

11 √3 - 9 √3 = 2 √3

Explanation: Find the factors of each number

363 factors are 33, and 11

Find which one you can take the square root from which is 33 and that is how you get 11 √3

3 √27 can be simplified more because the factors of 27 are 9, 3 take the square root of 9. And multiply the leftover 3 with the outside number which is also 3. Then you get 9 √3

Now just subtract

11 √3 - 9 √3

= 2 √3

Sorry if this is confusing but I hope it helps !!

You might be interested in

The equation y =

-Dominant- [34]

Answer:

The constant of proportionality k = 12

Hence, option A is true.

Step-by-step explanation:

We know that when 'y' varies directly with 'x', we get

y ∝ x

y = kx

Where 'k' is called the constant of proportionality.

In our case,

The given equation is

y = 12x

comparing with the equation y = kx, we can say

k = 12 which is the constant of proportionality.

Therefore, we conclude that:

The constant of proportionality k = 12

Hence, option A is true.

6 0

3 years ago

If C(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = C(x)/x. Consider the cost func

nadya68 [22]

Answer:

a) C(1,000)=288,491.11 $

b) c(1,000)=288.49 $/u

c) dC/dx(1,000)=349.74 $/u

d) x=100 u

e) c=220 $/u

Step-by-step explanation:

(a) Find the total cost at a production level of 1000 units.

$C(x) = 2,000 + 160x + 4x^{3/2}\\\\C(1,000)=2,000 + 160(1,000) + 4(1,000)^{3/2}\\\\C(1,000)=2,000+160,000+126,491.11= 288,491.11$

(b) Find the average cost at a production level of 1000 units.

$c(x)=C(x)/x\\\\c(1,000)=C(1,000)/1,000=288,491.11/1,000=288.49$

$\frac{dC}{dx} =0+160+4*(3/2)x^{3/2-1}=160+6x^{1/2}\\\\dC/dx|_{1,000}=160+6*(1,000)^{1/2}=160+189.74=349.74$

(d) Find the production level that will minimize the average cost.

$c=2,000x^{-1}+160+4x^{1/2}\\\\dc/dx=2,000(-1)x^{-2}+0+4(1/2)x^{-1/2}=0\\\\-2,000x^{-2}+2x^{-1/2}=0\\\\2x^{-1/2}=2,000x^{-2}\\\\x^{-1/2+2}=1,000\\\\x^{3/2}=1,000\\\\x=1,000^{2/3}=100$

(e) What is the minimum average cost?

$c(x) = 2,000/x + 160 + 4x^{1/2}\\\\C(100)=2,000/100 + 160 + 4(100)^{1/2}=20+160+40=220$

5 0

3 years ago

Ursula bought 9 dozen rolls of first aid tape for the health office. The rolls were divide equally into 4 boxes.

Vilka [71]

A dozen is equal to 12 so you have to do 12 x 9 = 108.

108 ÷ 4 = 27 so there was 27 rolls in each box.

6 0

3 years ago

Which is the best estimate for the height of the candle after 1 hour?

salantis [7]

Answer:

about 5.5

Step-by-step explanation:

so 5cm. Just trust me i dont know how to explain but i know its right.

7 0

3 years ago

How many two-digit numbers are there in which the tens digit is greater than<br> the ones digit?

Dovator [93]

there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

<h3>How many 2-digit numbers are there in which the tens digit is larger than the ones digit?</h3>

A 2-digit number is written as:

a*10 + b

Where a and b are single-digit numbers.

Tens digit and ones digit refers to place values:

a is the tens digit, and b is the ones digit. The numbers with a larger tens digit than the ones digit are:

98, 97, 96, 95, 94, 93, 92, 91, 90, 87, 86, 85, 84, 83, 82, 81, 80, 76, 75, 75, 74, 73, 72, 71, 70, 65, 64, 63, 62, 61, 60, 54, 53, 52, 51, 50, 43, 42, 41, 40, 32, 31, 30, 21, 20, 10.

We can see that there are 46 numbers in that list, so we conclude that there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

If you want to learn more about place values:

brainly.com/question/12386995

#SPJ1

7 0

1 year ago