Answer:
3960.4 bacteria
Step-by-step explanation:
The formula to solve the above question is given as:
P(t) = Po (2) ^t/k
P(t) = Population after time t = ?
Po = Initial population = 650 bacteria
t = Time in days = 7.3 days
k = doubling time = 2.8 days
P(t) = 650 × (2)^7.3/2.8
P(t) = 650 × 2^2.6071428571
P(t) = 650 × 6.0929582599
P(t) = 3960.4228689 bacteria.
Approximately = 3960.4 bacteria
Therefore, the number of bacteria the researcher will have after 7.3 days if they started with 650 bacteria is 3960.4 bacteria.
15% = 0.15
15.50 * 0.15 = 2.325
15.50 + 2.325 = 17.825
17.825 rounded to $17.83
Answer:
1. 4y-12
2. c
For #1 you distribute the 4 to the y and the 3. 4 times 3 equals 12.
For #2 you factor out the 3 and you get 3(5x+1)
Well, to factor out we have to find the gratest common factor of 54 and 24 which is 6. then divide both numbers by that number
54/6=9 24/6=4
6(9a+4b) is your final answer
