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ipn [44]
3 years ago
13

Help (f o g)(x) part 1 and pet two being domain

Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0
Sent a picture of the solution to the problem (s).

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Please people help me
Musya8 [376]

Answer:

x > 60

Step-by-step explanation:

From the picture attached,

An arrow starting with a hollow circle from x = 60, directing towards positive numbers (greater than 60).

So, hollow circle will represent an inequality with no sign of 'equal to' and arrow will represent the sign of greater than (As moving ahead of 60).

Inequality representing the picture will be,

x > 60

3 0
3 years ago
Two squares as shown below
zheka24 [161]

Answer:

3rd one

Step-by-step explanation:

any 2 squares are congruent since all four sides of any square are congruent

8 0
3 years ago
A number is chosen at random from 1 to 25. Find the probability of selecting an odd number or multiples of 5. *
Ymorist [56]

Answer:

Odd number: 13/25 (52%)

Multiples of 5: 5/25 (20%)

Step-by-step explanation:

There are 13 odd numbers between 1 and 25 so you have a 13/25 chance which is 52% (13/25 = 0.52). There are 5 multiples of 2 between 1 and 25 so you have a 5/25 chance which is 20% (5/25 = 0.2).

8 0
3 years ago
Consider the following functions. f1(x) = x, f2(x) = x2, f3(x) = 2x − 4x2 g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, a
bekas [8.4K]

9514 1404 393

Answer:

  • (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
  • NOT linearly independent

Step-by-step explanation:

We want ...

  c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0

Substituting for the fn function values, we have ...

  c1·x +c2·x² +c3·(2x -4x²) ≡ 0

This resolves to two equations:

  x(c1 +2c3) = 0

  x²(c2 -4c3) = 0

These have an infinite set of solutions:

  c1 = -2c3

  c2 = 4c3

Then for any parameter t, including the "trivial" t=0, ...

  (c1, c2, c3) = (-2t, 4t, t)

__

f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)

7 0
2 years ago
How do i add 1 1/6+ 3/5
Ierofanga [76]
You would change the denominator and get the lowest common denominator. Thos would be 30. You would do 11/6 x 5/5 = 55/30. Then do 3/5 x 6/6 = 18/30. Then add 55/30 + 18/30 = 73/30 and simplify.
3 0
4 years ago
Read 2 more answers
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