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3 years ago

What is the lateral surface area of the square pyramid represented by this net?

Mathematics

1 answer:

ddd [48]3 years ago

8 0

The surface area is 340ft^2

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What is the measure of minor arc BD?

Vaselesa [24]

Answer:

$minor\ arc\ BD=100^o$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

A circumscribed angle is the angle made by two intersecting tangent lines to a circle

In this problem

BC and CD are tangents to the circle

BC=CD ----> by the Two Tangent Theorem

That means

Triangle ABC and Triangle ADC are congruent

$m\angle BAC=m\angle DAC$

Find the measure of angle BAC

In the right triangle ABC

$m\angle BAC+m\angle BCA=90^o$

substitute given value

$m\angle BAC+40^o=90^o$

$m\angle BAC=90^o-40^o=50^o$

Find the measure of angle BAD

$m\angle BAD=2m\angle BAC$

$m\angle BAD=2(50^o)=100^o$

Find the measure of minor arc BD

we know that

$minor\ arc\ BD=m\angle BAD$ -----> by central angle

therefore

$minor\ arc\ BD=100^o$

8 0

3 years ago

Read 2 more answers

A circular sector has a central angle of π6 radians and a radius of 9 ft.

ohaa [14]

Answer:

$\approx \: 21.2 \: {ft}^{2}$

Step-by-step explanation:

$central \: \angle = \frac{\pi ^{c} }{6} = 30 \degree \\ \\ area \: of \: the \: sector = \frac{30 \degree}{360 \degree} \times \pi {(9)}^{2} \\ \\ = \frac{1}{12} \times 3.14 \times 81 \\ \\ = \frac{1}{12} \times 254.34 \\ \\ = 21.195 \: {ft}^{2} \\ \\ \approx \: 21.2 \: {ft}^{2}$