Answer:
because it provides you a lot of storage and the post production equipment to handle it and it is used to do big projects
Explanation:
so l know this much it is correct please mark me brainllest
Answer: True
Explanation:
Virtual memory is the secondary storage memory and this type of memory are addressed as main part of the memory.
When the virtual memory copying in the physical memory then, at that time the operating system divide the memory into the file page with the address and definite size number. Then, the each page are store in a disk.
When this page are required then, the operating system copy from disk to main memory and then, the virtual address are converted into the real address.
Answer:
if and and not and or ans all
Since Anil needs to show the overlap of people who live in a certain neighborhood in his city that supports a specific political candidate, the type of conceptual diagram which he should use is a: B: Venn diagram.
<h3>What is a Venn diagram?</h3>
A Venn diagram can be defined as a circular graphical (visual) tool that is typically used for representing, logically comparing and contrasting two (2) or more finite sets of data such as objects, students, events, voters, concepts, people, etc.
In this context, we can reasonably infer and logically deduce that a Venn diagram is a type of conceptual diagram which can be used by Anil in illustrating the overlap of people who are living in a certain neighborhood in his city and supports a specific political candidate in an election.
Read more on Venn diagram here: brainly.com/question/24581814
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Answer:
#include <iostream>
using namespace std;
void PrintPopcornTime (int bagOunces){
if (bagOunces < 2){
cout << "Too small"<<endl;
}
else if (bagOunces > 10){
cout << "Too large"<<endl;
}
else{
cout << bagOunces*6 <<" seconds"<<endl;
}
}
int main(){
PrintPopcornTime(7);
return 0;
}
Explanation:
Create a function called PrintPopcornTime that takes one parameter, bagOunces
Check the bagOunces using if-else structure. If it is smaller than 2, print "Too small". If it is greater than 10, print "Too large". Otherwise, calculate and print 6*bagOunces followed by " seconds".
Call the function in the main function with parameter 7. Since 7 is not smaller than 2 or not greater than 10, "42 seconds" will be printed.
