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3 years ago

If 15 divided c =3 how many times would c have to be subtracted from 15 in order for the answer to be zero?

Mathematics

1 answer:

Nataliya [291]3 years ago

3 0

Step-by-step explanation:

If 15÷C=3 , 15÷3=5 and 15-5=10, 10-5=5, 5-5=0 The answer is 3

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Can someone help me find x pleaseeee

Nataly [62]

You can use the pythagoras’ theorem and just look at one right triangle.
The dimensions for one of the right triangles is (x/2), 8, and square root of 80.

a^2 + b^c = c^2
when c is the square root of 80.

Plug everything in
(x/2)^2 + 8^2 = (square root of 80)^2

That is equivalent to
((x^2)/4) + 64 = 80

Solve for x
((x^2)/4) = 16

Multiple by 4 on each side
x^2 = 64

Take the square root and you have you’re final answer
x = 8

3 0

4 years ago

A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute

GREYUIT [131]

Answer:

(a) Null Hypothesis, $H_0$ : $\sigma$ = 10 beats per minute

Alternate Hypothesis, $H_A$ : $\sigma\neq$ 10 beats per minute

(b) The value of chi-square test statistics is 35.704.

(c) P-value = 0.4360.

(d) We conclude that the pulse rates of men have a standard deviation equal to 10 beats per minute.

Step-by-step explanation:

We are given that a simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute.

If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute.

Let $\sigma$ = population standard deviation for the pulse rates of men.

(a) So, Null Hypothesis, $H_0$ : $\sigma$ = 10 beats per minute {means that the pulse rates of men have a standard deviation equal to 10 beats per minute}

Alternate Hypothesis, $H_A$ : $\sigma\neq$ 10 beats per minute {means that the pulse rates of men have a standard deviation different from 10 beats per minute}

The test statistics that will be used here is One-sample chi-square test for standard deviation;

T.S. = $\frac{(n-1)\times s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, s = sample standard deviation = 10.1 beats per minute

n = sample of men = 36

So, the test statistics = $\frac{(36-1)\times 10.1^{2} }{10^{2} }$ ~ $\chi^{2}__3_5$

= 35.70 4

(b) The value of chi-square test statistics is 35.704.

(c) Also, the P-value of the test statistics is given by;

P-value = P( $\chi^{2}__3_5$ > 35.704) = 0.4360

(d) Since the P-value of our test statistics is more than the level of significance as 0.4360 > 0.10, so we have insufficient evidence to reject our null hypothesis as the test statistics will not fall in the rejection region.

Therefore, we conclude that the pulse rates of men have a standard deviation equal to 10 beats per minute.

3 0

4 years ago

What fraction is equivalent to 52/13?

Varvara68 [4.7K]

52/13 is equal to 4/1.

7 0

4 years ago

Read 2 more answers

a construction worker needs to put a rectangular window in the side of a building. he knows from measuring that the top and bott

Cloud [144]

The other diagonal would be 13 feet as well because it is a rectangle.