Question

An eagle is flying from point A to point B in order to catch a sparrow. Its flying trajectory is a parabola shape

Answer 1

Answer:

From 10 to 20 meters.

Step-by-step explanation:

1) If the sparrow has a parabolic trajectory then it must be actually:

$y=-5\left ( x+6 \right )^{2}+10$

2) If the eagle is at 20 meters high, then we write:

$y=20$

Since the exact x coordinate was not given.

But since it wants to get the sparrow

3) If we expand the equation we have:

$-5x^{2}-60x-170=0\\\\X_{v}=\frac{-b}{2a}=\frac{60}{-10} = -6\\Y_{v}=\frac{-\Delta}{4a} =\frac{-200}{-20} =10$

Since the maximum point is equal to 10. The distance where the sparrow is flying ranges from 10 to 20 meters to the eagles spot.

$10\leq d \leq20 \:or \:[10,20]$

4) Since the x coordinate was not given then we can neither precisely calculate the distance where A is nor where B is located.