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Schach [20]
3 years ago
6

PLEASEE HELP!!!!

Mathematics
2 answers:
Vadim26 [7]3 years ago
7 0

Answer:

C.220

Step-by-step explanation:

220 is exactly divisible by 22.And it is about 10 times not in the 30s.So it cannot be 660,or 330.

Elza [17]3 years ago
6 0

Answer:

the answer would be A

Step-by-step explanation:

hope it helps pls give brainly

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Compare this graph to the previous graphs in lesson 1 and 2. Explain how the are different or similar.
Andrew [12]

Answer:

Hello!

You can compare graphs by looking at their rate of change, and y intercept.

Another way you can compare graphs is that you can see if both graphs' lines intersect. I hope this helps you! :)

Have a nice day! :D

3 0
3 years ago
. A conductor with a diameter of 100 mils has an area of
Zielflug [23.3K]
In order to answer the question, you need to know the area of a circle.
Area = pi * r^2
Area = 3.14 * (100/2) ^ 2
Area = 3.14 * 50^2
Area = 7850 mils^2 = 0.00785 in^2
7 0
3 years ago
Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m
marshall27 [118]

Answer:

1. 0.0000454

2. 0.01034

3. 0.0821

4. 0.918

Step-by-step explanation:

Let X be the random variable denoting the number of passengers arriving in a minute. Since the mean arrival rate is given to be 10,  

X \sim Poi(\lambda = 10)

1. Requires us to compute

P(X = 0) = e^{-10} \frac{10^0}{0!} = 0.0000454

2.  We need to compute P(X \leq 3) = P(X =0) + P(X =1) + P(X =2) + P(X =3)

P(X =1) = e^{-10} \frac{10^1}{1!} = 0.000454

P(X =2) = e^{-10} \frac{10^2}{2!} = 0.00227

P(X =3) = e^{-10} \frac{10^3}{3!} = 0.00757

P(X \leq 3) =0.0000454+ 0.000454 + 0.00227 + 0.00757 = 0.01034

3. The expected no. of arrivals in a 15 second period is = 10 \times \frac{1}{4} = 2.5. So if Y be the random variable denoting number of passengers arriving in 15 seconds,

Y \sim Poi(2.5)

P(Y=0) = e^{-2.5} \frac{2.5^0}{0!} = 0.0821

4. Here we use the fact that Y can take values 0,1, \dotsc. So, the event that "Y is either 0 or \geq 1" is a sure event ( i.e it has probability 1 ).

P(Y=0) + P(Y \geq 1) = 1 \implies P(Y \geq 1) = 1 -P(Y=0) = 1 - 0.0821 = 0.918

3 0
3 years ago
What is the solution of the inequality?
OleMash [197]
Multiply both sides by 5 to go from this
x/5 >= -2
to this
x >= -10

The notation ">=" without quotes means "greater than or equal to"

To graph this, plot -10 on the number line as a closed circle. Shade to the right of this closed circle. The shaded region represents all the solutions to the original inequality. 

Final Answer: Choice D
4 0
3 years ago
Find the height of the 6 -story building
astraxan [27]

Answer:

60 to 90 feet tall

Step-by-step explanation:

i just looked it up

4 0
3 years ago
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