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sveticcg [70]
3 years ago
15

Suppose your office gives you $200 to buy binders. Small binders cost $7 each. Large binders cost $8 each. Write the inequality

that describes how many of each kind of binder you can buy.
Mathematics
2 answers:
Shkiper50 [21]3 years ago
8 0
25 of large ones and 28 small ones
nikitadnepr [17]3 years ago
6 0
$7x+$8y is equal to or less than $200
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What is the equation of the following line written in slope intercept form
pentagon [3]

Answer:

The equation can be y = -7x+11

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Draw as many different F patterns as you can!
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Step-by-step explanation: why tutugug I did it for you too lol I was like what

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2 years ago
Which is the standard form of the equation of the parabola that has a vertex of (–4, –3) and a directrix of x = 2?
Zielflug [23.3K]

Answer:

Equation of the parabola is \left(y+3\right)^{2}=-24(x+4)

Step-by-step explanation:

We have to find the equation of a parabola with vertex is (-4,-3) and a directrix x=2.

As vertex is (-4,-3) that means parabola is in third quadrant.

So the standard formula of the parabola will be y²= -4px through origin (0,0).

But when a parabola is shifted from origin to the left of y axis so the equation will be (y-shifting form y axis)² = -4(distance between vertex and directrix)(x-shifting from x axis)

\left\{y-(-3)\right\}^{2}=(-4\times 6)\left\{x-(-4)\right\}

\left(y+3\right)^{2}=-24(x+4).



5 0
4 years ago
Read 2 more answers
Suppose that the cost of a rental car is $65 for a week plus 0.15 per mile driven.
IceJOKER [234]

You have the following equation for the cost of renting a car for x number of miles driven:

y = 0.15x + 65

If you travel 70 miles, then, x = 70 and you obtain for the cost y:

y = 0.15(70) + 65

y = 10.5 + 65

y = 75.5

Hence, the cost of renting a car to drive 70 miles is $75.5

3 0
1 year ago
A 10.0 kg and a 2.0 kg cart approach each other on a horizontal frictionless air track. Their
Flura [38]

the  final speed in m/s of the 10.0 kg is 2.53 m/s .

<u>Step-by-step explanation:</u>

Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their  total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the  final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:

We know that in an elastic collision :

⇒ Total kinetic energy before collision  = Total kinetic energy after collision

⇒ 96 = \frac{1}{2}M_1(v_1)^2 + \frac{1}{2}M_2(v_2)^2

⇒ 96 = \frac{1}{2}(10)(v_1)^2 + \frac{1}{2}(2)(8)^2

⇒ 96=5(v_1)^2 + 64

⇒ 5(v_1)^2  =32

⇒ (v_1)^2  =6.4

⇒ v_1  =2.53 m/s

Therefore , the  final speed in m/s of the 10.0 kg is 2.53 m/s .

8 0
3 years ago
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