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3 years ago

F(x)=4x+1 and g(x)=x^2-5find(f-g)(x)

Mathematics

1 answer:

Vinvika [58]3 years ago

4 0

Answer:

Step-by-step explanation:

Given f(x)=4x+1 and g(x)=x²-5

(f-g)(x) is derived by taking the difference of both functions

(f-g)(x) = f(x)-g(x)

(f-g)(x) = 4x+1 - (x²-5)

(f-g)(x) = 4x+1-x²+5

(f-g)(x) = -x²+4x +6

This gives the requires expression

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3 years ago

Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean

Leno4ka [110]

Answer:

a = $\sqrt{7}$

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.:

<em>Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean theorem and then find the values of the six trigonometric functions for angle B. when b=3 and c=4</em>.

My answer:

We will Pythagoras theorem, which states that the sum of squares of two legs of a right triangle is equal to the square of the hypotenuse of right triangle. Because the question says that ABC is a right triangle.

$a^2+b^2=c^2$

Given that: b=3 and c=4

$a^2+3^2=4^2a^2+9=16a^2+9-9=16-9a^2=7$

so a = $\sqrt{7}$

We know that tangent relates opposite side of a right triangle with adjacent side.

$\text{tan}(B)=\frac{a}{b}\\\text{tan}(B)=\frac{\sqrt{7}}{3}$

Please have a look at the attached photos.

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