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STALIN [3.7K]
3 years ago
5

What is the answer?​

Mathematics
2 answers:
Law Incorporation [45]3 years ago
6 0

Step-by-step explanation:

Since CD is the perpendicular bisector of AB, AD = DB.

Hence 6x - 2 = 2x + 18 and x = 5.

romanna [79]3 years ago
3 0

Answer:

x = 5

Step-by-step explanation:

You might be interested in
PLEASE HELP!!!!
Bogdan [553]

Answer:

Step-by-step explanation:

We would apply the formula for binomial distribution which is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - r) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 18% = 18/100 = 0.18

q = 1 - p = 1 - 0.18

q = 0.82

n = 5

Therefore,

P(x ≤ 2) = p(x = 0) + p(x = 1) + p(x = 2)

P(x = 0) = 5C0 × 0.18^0 × 0.82^(5 - 0)

P(x = 0) = 0.37

P(x = 1) = 5C1 × 0.18^1 × 0.82^(5 - 1)

P(x = 1) = 0.41

P(x = 2) = 5C2 × 0.18^2 × 0.82^(5 - 2)

P(x = 2) = 0.18

Therefore,

P(x ≤ 2) = 0.37 + 0.41 + 0.18 = 0.96

5 0
2 years ago
What is 708569 to the nearest ten thousands
gregori [183]
70,000
The 0 means that it stays the same.
Hope it helps.
6 0
3 years ago
How do you solve this?
vagabundo [1.1K]
You would add up all of the sides by combining like terms. Let me know if you want the answers for it.
6 0
2 years ago
Bob Ross has a charge card. Ross's previous monthly balance if $167.42. He made a payment of $159.15. There is no finance charge
dolphi86 [110]

Answer:

According to your question, the new balance is $8.27

Step-by-step explanation:

$167.42 - $159.15 = $8.27

7 0
3 years ago
Hey can you please help me posted picture of question
Ira Lisetskai [31]
Answer:
40x² + 65x + 25

Explanation:
We will just multiply each term from the first bracket by each term from the second and then combine like terms to get the final expression.

This would be done as follows:
(5x + 5)(8x + 5)
5x(8x) + 5x(5) + 5(8x) + 5(5)
40x² + 25x + 40x + 25
40x² + 65x + 25

Hope this helps :)
6 0
3 years ago
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