(3x-2)(4x+1)= Please answer!!!

Mathematics

1 answer:

Mazyrski [523]3 years ago

8 0

Answer:

Do you what the graph?

Step-by-step explanation:

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Someone please help me on this I'm unsure if my answer is correct

mafiozo [28]

Answer:

A. length = 23 cm; width = 5 cm

Step-by-step explanation:

So if 4 times the width would be $4w$ and 3 more than would be $+ 3$ , the equation would be $l = 4w + 3$ . If the perimeter is 56, then the new equation, $2(4w + 3) + 2(w) = 56$ can be formed. This simplifies to $8w + 6 + 2w = 56$ , then to $10w + 6 = 56$ , then to $10w = 50$ , and finally, $w = 5$ . So the width is 5, and now plug it into the first equation.

$l = 4(5) + 3$ , becomes $l = 20 + 3$ , becomes $l = 23$ .

So the dimensions are: length = 23 cm, width = 5 cm.

*And just to be sure, $2(23 + 5) = 2(28) = 56$ which is correct.

4 0

2 years ago

After a dreary day of rain, the sun peeks through the clouds and a rainbow forms. You notice the rainbow is the shape of a parab

Gekata [30.6K]

We can answer the first part of the question not taking intersecting function into account. The domain of $y=-x^{2}+36$ is all the numbers, x∈(-∞, +∞) and the range is y∈(-∞, 36]. We can observe these results with the help of a graph, as well. Since we are talking about the rainbow, the values above the ground level will make sense. In this case, we will take into account the range as it changes between 0 and 36, included and the domain between -6 and 6. Here (0;36) is the y-intercept and (-6;0) and (6;0) are the x-intercepts of the parabola.

Since in our problem, the linear function that intersects parabola is not given, we have to provide it by ourselves according to the conditions of the problem. It could be any line intersecting parabola in two points. One important point is that the y-intercept has to be no more than 36. Considering these conditions, we can set our linear function to be $y=0.5x+5$ . We can observe the points that we included in the table (they have been given with orange dots in the graph and the table is attached below). We can see that the values of the function (values of y) are positive. Indeed, we are discussing the part of the rainbow above the ground level.

The system of equations with linear and quadratic functions has got two solutions and we can observe that result from the graph. The solutions are (-5.823; 2.088) and (5.323; 7.662). The solutions are the intersection points.