Question

Given the vector equation ????(t)=(4−3t)????+(−5+t)????+(3−t)????, rewrite this in terms of the parametric equations for the line.x(t)=
y(t)=
z(t)=

Answer 1

Answer:

The parametric equations for the line.x(t)=

y(t)=

z(t)=

is  

 $\= r (t) = \left \{ {{x(t)= 4-3t} \atop {y(t)= -5+t}} \atop {z(t)=3-t}} \right \}$

Step-by-step explanation:

From the question we are told that

      the given equation is

                $\= r(t) = (4-3t) + (-5 + t) + (3-t)$

This given equation can be represented as

             $\= r (t) = [4 -3t , -5+t,3-t]$

Generally this equation can be represented in terms of the parametric equations as follows

   $\= r (t) = \left \{ {{x(t)= 4-3t} \atop {y(t)= -5+t}} \atop {z(t)=3-t}} \right \}$

This above equation is obtained by assigning each component of r(t) to each  line