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Pie
2 years ago
8

Simplify 2(x - 3) + 7(x + 2). 9x - 8 9x + 3 9x + 8

Mathematics
2 answers:
Aleks04 [339]2 years ago
7 0
The answer is 9x+8. if you distripute the 2, you get 2x-6. if you distribute the 7, you get 7x+14. then you combine like terms ans get 9x+8

Elza [17]2 years ago
6 0
2(x-3)+7(x+2) now you time 2*x which you will get 2x, then you will times 2*-3 which is -6, now you times 7by x and you get 7x and times 7by 2 and you get 14 it should look like this

2x-6+7x+14 and then you add 2x+7x which is 9x then 14+-6 that is 8 it should look like this

9x+8
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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
2 years ago
Read 2 more answers
Help would be appreciated :)
Orlov [11]

Answer:

3y-x=-18

Step-by-step explanation:

3y-x=-18

3y=x-18

y=1/3x-6

Parallel lines have the same slope

8 0
3 years ago
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ArbitrLikvidat [17]

Answer:

81

Step-by-step explanation:

3^2

3 × 3

= 9

3^2

3 × 3

= 9

9 × 9

= 81

3 0
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Lostsunrise [7]
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shepuryov [24]

Answer:

Step-by-step explanation:

Answer D I just fot it right on my test

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