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3 years ago

8

Simplify 2(x - 3) + 7(x + 2). 9x - 8 9x + 3 9x + 8

2 answers:

Aleks04 [339]3 years ago

7 0

The answer is 9x+8. if you distripute the 2, you get 2x-6. if you distribute the 7, you get 7x+14. then you combine like terms ans get 9x+8

Elza [17]3 years ago

6 0

2(x-3)+7(x+2) now you time 2*x which you will get 2x, then you will times 2*-3 which is -6, now you times 7by x and you get 7x and times 7by 2 and you get 14 it should look like this

2x-6+7x+14 and then you add 2x+7x which is 9x then 14+-6 that is 8 it should look like this

9x+8

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pychu [463]

Answer :

The value of q for, the given quadratic equation is 40

Step-by-step explanation :

Given quadratic equation as :

x² - 14 x + q = 0

And , Difference between the roots of equation is 6

Let A , B be the roots of the equation

So, A - B = 6

The roots of the quadratic equation ax² + bx + c = 0 as can be find as :

x = $\frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

x = $\frac{14\pm \sqrt{(-14)^{2}-4\times 1\times q}}{2\times 1}$

or, x = $\frac{-14\pm \sqrt{196-4 q}}{2}$

Or, x = $\frac{-14\pm \sqrt{196-4 q}}{2}$

So , The roots are

A = $-7 + \frac{\sqrt{196-4q}}{2}$

And B = $-7 - \frac{\sqrt{196-4q}}{2}$

∵ The difference between the roots is 6

So, A - B = 6

Or, ( $-7 + \frac{\sqrt{196-4q}}{2}$ ) - ( $-7 - \frac{\sqrt{196-4q}}{2}$ ) = 6

Or, ( - 7 + 7 ) + 2 ( $\sqrt{196-4q}$ = 6

Or, 0 + 2 ( $\sqrt{196-4q}$ = 6

∴ 196 - 4 q = 36

or, 4 q = 196 - 36

or 4 q = 160

∴ q = $\frac{160}{4}$

I.e q = 40

S0, The value of q = 40

Hence The value of q for, the given quadratic equation is 40 . Answer

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3 years ago