Answer:
2 to the power of one sixth
Step-by-step explanation:
Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:
![\sqrt[n]{x} = {x}^{ \frac{1}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%7D%20%20%3D%20%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7Bn%7D%20%7D%20)
So you can rewrite the given fraction as

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

Since

the answer is
![{2}^{ \frac{1}{6} } \: or \: \sqrt[6]{2}](https://tex.z-dn.net/?f=%20%7B2%7D%5E%7B%20%5Cfrac%7B1%7D%7B6%7D%20%7D%20%20%5C%3A%20or%20%5C%3A%20%20%5Csqrt%5B6%5D%7B2%7D%20)
We know that a triangle adds up to 180 degrees.
Here, 130 is a vertical angle so on the opposite side the triangle makes, it is also 130. Then we could add 130 to 25
130 + 25 = 155
Now let’s subtract this from 180.
180 - 155 = 25.
X is a supplementary angle to 25 so subtract 25 from 180.
180 - 25 = 155
X = 155.
x adds 1 and y subtracts by 6
You would subtract the y intercepts then the x intercepts. Subtract 13-6 then divide it by 9-6. That gets you a slope of 7 over 3
Hi!
-6+7x-6x = 3
-6+x = 3
x = 3+6
x = 9
Answer:
x = 9