Answer:
the answer is D
Step-by-step explanation:
i got it right
Answer:
average atomic mass = 207.2172085 amu
Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.
For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)
The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
+ 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu
Hope this helps :)
<span>y-2>1/2(x-2) can be expanded as follows: y - 2 > (1/2)x - 1
Mult. all terms by 2 to remove the fractions:
2y - 4 > x - 2
Add 4 to both sides: 2y > x + 2
Div. both sides by 2: y > (1/2)x + 1 (answer)</span>
Answer:
92.5
Step-by-step explanation:
18.5% = 0.185
0.185 x 500 = 92.5
Hope that helps!
For the triangle, the shaded part, both the height and base are 12, so the area of it is:
1/2 (12 x 12) = 72
And the area of the whole square is 144
But what we’re looking for is the area of the unshaded region. So to find it, we’ll need to subtract the shaded from the total. So:
144 - 72 = 72
Thus, the area of the unshaded region is 72
