Answer:
(2, -10)
Step-by-step explanation:
so first i find the axis of symmetry using the equation x= -b/2a
in this problem
a=3
b= -12
c= 2
- (-12)/ 2(3) = 2
2 will be the x point for your vertex
you then plug in your x point into the original equation and solve for y
y = 3(2)^2 - 12(2) +2
y = -10
Vertex is then (2, -10)
Answer:
y + 1 = 3(x - 5) Answer
Step-by-step explanation:
<u><em>Find the slope of the perpendicular line.</em></u>
m1 * m2 = - 1
m1 = - 1/3
m2 is the slope of the perpendicular
(-1/3) * m2 = - 1 Multiply both sides by -3
-(3)(-1/3) * m2 = -1 * -3
m2 = 3
The slope of the perpendicular line is 3
<em><u>Find the equation of the line.</u></em>
m = (y - y1)/(x -x1)
y - y1 = m(x - x1) is the equation of the line.
y1 =5
x1 = - 1
(y - - 1) = 3(x - 5)
y + 1 = 3(x - 5) Answer
Answer:
1. 10 : 24 = 5 : 12 = 20 : 48 = 40 : 96
2. 2 : 3 : 5 = 4 : 6 : 10 = 8 : 12 : 20
This is a great question, but it's also a very broad one. Please find and post one or two actual rational expressions, so we can get started on specifics of how to find vertical and horiz. asymptotes.
In the case of vert. asy.: Set the denom. = to 0 and solve for x. Any real x values that result indicate the location(s) of vertical asymptotes.
One is 5% of 20 I believe
