1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vesna_86 [32]
3 years ago
5

Find domain and range of graph below! Help please!

Mathematics
1 answer:
olga_2 [115]3 years ago
5 0

Answer:

not sure

Step-by-step explanation:

You might be interested in
Please prove this........​
Crazy boy [7]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

                                    → sin C = sin (A + B)              cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C

\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C

\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C

\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]

\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

7 0
3 years ago
PLEASE HELP I WILL GIVE EXTRA POINTS
Evgen [1.6K]

Answer:

  C

Step-by-step explanation:

A relation is a function if each input gives exactly one output. There is one price for each number of pounds, so the relation is a function.

__

<em>Additional comment</em>

Relations expressed in terms of ordered pairs or tables can be identified as "not a function" if any input (x) value is repeated. Relations expressed as a graph will be "not a function" if any vertical line intersects the graph at more than one point. (This is called "the vertical line test.")

The cost function in this case is a straight line through the origin. It has a slope of $5.99/lb. Any polynomial relation will be a function.

6 0
2 years ago
Stock bottles should be moved on the shelves A. by placing new stock behind old stock so stock closest to expiration gets used f
Vinvika [58]
A. By placing new stock behind old stock
6 0
3 years ago
How many inches of square paper did Benjamin use to wrap the box?
Dominik [7]
Two times the length of the longest edge.
5 0
3 years ago
Which of the following statements is false?
Alina [70]

Answer:

C is false

Step-by-step explanation:

Example 3 is odd but 6 is equal.

3•6 is 18

18 is even

3 0
3 years ago
Other questions:
  • Brainers, please help me please
    10·1 answer
  • What division sentence means the same as the following subtraction sentences? 12-4=8, 8-4=4,4-4=0
    5·1 answer
  • Solve x2 – 8x + 15 &lt; 0.
    15·2 answers
  • A computer and printer cost a total of $939. The cost of the computer is two times the cost of a printer. Find the cost of each
    11·1 answer
  • A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee ca
    15·1 answer
  • What is the additive inverse of non complex 9
    7·1 answer
  • I need help asapppp please help mee
    9·2 answers
  • Please help me...............
    7·1 answer
  • X &lt; -4.8
    5·2 answers
  • Figure ABCD is a rhombus.
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!