Answer: 4
Step-by-step explanation:
Answer: The Fuschia Bot clicks _6_ times in 0.75 sec,
Step-by-step explanation:
Multiply the unit rate by time:
.75 sec × 8 clicks/sec
Seconds cancel. .75(8) = 6 clicks
Answer:

Step-by-step explanation:
The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.
To find the
percentile for the television weights, use the formula:
, where
is the average of the set,
is some constant relevant to the percentile you're finding, and
is one standard deviation.
As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute
,
, and
:

Therefore, the 90th percentile weight is 5.1282 pounds.
Repeat the process for calculating the 10th percentile weight:

The difference between these two weights is
.
You can verify this by plugging the numbers into the Pythagorean theorem,

, where c is the hypotenuse (the longest side, in this case 53).
So it would be:

The equation is true.
2809 = 2809
5% if you set up a proportion, it helps you out more.