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Sliva [168]
3 years ago
13

Tim's phone service charges $24.07 plus an additional $0.17 for each text message sent per month. If Tim's phone bill was $28.32

, which equation could be used to find how many text messages, x, Tim sent last month?
A. $0.17x - $24.07 = $28.32
B. $24.07x + $0.17 = $28.32
C. $0.17x + $24.07 = $28.32
D. $24.07x - $0.17 = $28.32
Mathematics
2 answers:
quester [9]3 years ago
7 0

C becuase x is each text you would multiply it .17 and then add it to 24.07 the bill each month

valkas [14]3 years ago
6 0

I'm pretty sure it would be C


because 0.17 is how much he has to pay for each message sent and if x is the total messages he sends then it should be 0.17X+24.07

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5 0
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Read 2 more answers
Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)

We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
pr=p-r=<5-8,-1-6,1-0>=<-3,5,1>

The vector product pq x pr gives a vector perpendicular to both pq and pr.  This vector is the normal vector of a plane passing through all three points
pq x pr
=
  i   j   k
-4 -2 -4
-3  5  1
=<-2+20,12+4,-20-6>
=<18,16,-26>

Since the length of the normal vector does not change the direction, we simplify the normal vector as
N = <9,8,-13>

The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).

The equation of the required plane is therefore
Π :  9(x-9)+8(y-1)-13(z-5)=0
expand and simplify, we get the equation
Π  :  9x+8y-13z=24

Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.

3 0
3 years ago
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